Recent content by questions_uk

Hi. How would you go about doing negative powers on the windows calculator? For example if you wanted to calculate 10 x 10 ^ - 3 x 2 for example what input would you use on the windows calculator? Thanks.

Thanks. Any other suggestions are appreciated.

Hi there. If there is to be a back projector system behind a screen (such as a car instrument panel), in order for the information to be displayed in the correct sequence I'm thinking some sort of horizontal/convex lens will need to be used in order to invert the information in the horizontal...

Thanks for your help. I used the resolution of the dosplay to work out the horizontal dimensions of it.

Thanks for your help! I basically used the other magnification rule you gave and assumed a value for the horizontal dimension. This could then be be used with M = v / u thus calculating u as v and M are already known and obtaining a v value. With the u and f values I used 1 / f = 1 / u + 1...

Hi. If using: f (focal length) = a / ( 2 x arctan (theta / 2)) where a = 13 and is the Field of View the value I get for the focal length is 0.03 and this seems too small. Unless the calculation has not been done right? Thanks.

Hi. Some of the equations I've got include: 1 / f = 1 / v + 1 / u And M = v / u Also am not sure if this is related to it but Numerical Aperture / F number N = F / D Thanks!

That's what I thought, and then compare the display with the screen. However, the magnification depends on U and V which I think are the lengths from the display to the lens and from the lens to the screen.

Ah ok thanks. So if you had 24 bit colour, how would you work out the number of bits to each pixel? Or is it just 24 bits per pixel? Thanks.

Thanks for the reply. Interestingly enough I also wondered whether the magnification would be taken into the account, as magnification is included in the notes. What was a bit weird was how it gave the diagonal dimension of the display and the horizontal dimension of the screen?

Thanks! So if you have an 8 bit colour system for example, this means 8 bits are dedicated to each pixel?

If you have an x bit SXGA colour display operating at an equivalent frame rate of x Hz, to calculate the data rate would you just multiply these two variables together? Thanks.

Hi. It asks to calculate the focal length range of a projector of square pixel SXGA is from 4 to 12 m from the screen. It gives the diagonal size of the display (in mm) as well as the horizontal size (in m). The thing that am not sure about is how the focal length would be calculated with the...

Thank you for your reply. Is the distance not from the lens to the screen? And would it not be 1/f = 1 / u + 1 / v? Am also not sure where triangles would come into calculating the focal length. Thanks.

Hi. There's a question that has given some variables which am not sure how to compute to some previous lens/optics equations. These are not the actual variable values by the way. If a projector (square pixel SXGA) has a diagonal size of 5 mm which uses a screen of 1 m in which the distances...