Recent content by Quincy

Ah ok. I was confusing it with the overdrive voltage; I thought they were the same thing.

I get that but what about the threshold voltage (Vth)? The overvoltage is the voltage across two transistor terminals minus the threshold voltage. Why don't we include it in the equation for VOV = VDS2max?

Isn't VOV = VGS - Vth, so shouldn't VOV2 = VGS2max - Vth? (or VOV2 = VDS2max - Vth) rather than VOV2 = VGS2max?

New question related to same circuit in the initial post: the solution manual states that VDS2max = VOV2 = VGS2 - Vth. My question is why is VDS2max = VOV2? Shouldn't VDS2 = VGS2 since the drain and gate of Q2 are connected?

New question concerning same circuit: Why is R = (VS2 + VGS2)/IREF? Shouldn't it be VD1/IREF?

Turns out the solution manual had it wrong... it should be VOV4 = -1.3 - (-1.5)

I have a simple conceptual question rather than an actual problem so pardon me for not using the provided template. There's a question in my Microelectronic Circuits book involving this circuit: where it states that Part of the solution involves this equation: VOV4 = VD4 - VS4 (equation...

Anyone? really need help with this one...

Homework Statement Consider an IP Router with four link interfaces numbered 0 to 3. Packets are to be forwarded according to the table: http://img688.imageshack.us/img688/4844/iproutertable.jpg Write down an IP forwarding table with ve entries that forwards packets to the correct...

Homework Statement h(t) = u(t) (the unit step function) x (t) = e-t The Attempt at a Solution There is only one interval where the two functions overlap, and that's from 0 to t. The integral from 0 to t of e-\tau d\tau = -e-t Doesn't look right to me... what am I doing wrong? EDIT: This is...

oops, I made a mistake with setting up the integral, the limits of the y integral should be x^2/v to infinity. One more question: How do you know when setting up the problem, if it's going to be P(V <= v) or P(V >= v)? How how does that effect how the integrals are set up?

Ohh I see... I drew a picture now and I got the limits for the x integral to be 0 to infinity and the limits for the y integral to be 0 to x^2/v. Then, when I solve the integral, I get: ve^(-x^2/v) (evaluated from 0 to infinity) + x^2 (evaluated from 0 to infinity), which gives me an...

The limits of the second integral would be x^2/V to infinity, right? I haven't drawn the picture, I don't know how to draw the picture given the information. How do I use the joint pdf to draw the picture?

Homework Statement Given: The joint probability distribution function of X and Y: f(x,y) = 2xe^(-y), x > 0, y > x^2 0, otherwise Obtain the pdf of V = (X^2)/Y The Attempt at a Solution The interval of V is (0,1) because Y is always...

don't both X1 and X2 have the same pdf?...