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Quincy
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I have a simple conceptual question rather than an actual problem so pardon me for not using the provided template.
There's a question in my Microelectronic Circuits book involving this circuit:
where it states that
Part of the solution involves this equation:
VOV4 = VD4 - VS4 (equation for overdrive voltage of Q4)
VOV4 = -1.5 - (-1.3)
My question is: Why is VD4 equal to -1.5 V and why is VS4 equal to -1.3 V? -1.3 V is the voltage at the drain of Q5, how did it become the voltage at the source of Q4?
There's a question in my Microelectronic Circuits book involving this circuit:
where it states that
voltages at the drain of Q2 can be as high as +1.3 V and voltages at the drain of Q5 can be as low as -1.3 V.
Part of the solution involves this equation:
VOV4 = VD4 - VS4 (equation for overdrive voltage of Q4)
VOV4 = -1.5 - (-1.3)
My question is: Why is VD4 equal to -1.5 V and why is VS4 equal to -1.3 V? -1.3 V is the voltage at the drain of Q5, how did it become the voltage at the source of Q4?