Recent content by randomphysicsguy123
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Vector Problem -- Addition of two vectors given in polar coordinates
It is not from an SAT prep book, it is from a free online SAT Physics site that provides example questions. Thus this is the real question. I am simply asking if I did it right and if not what did I do wrong and how to correct it.- randomphysicsguy123
- Post #11
- Forum: Introductory Physics Homework Help
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Vector Problem -- Addition of two vectors given in polar coordinates
This image was the one provided.- randomphysicsguy123
- Post #9
- Forum: Introductory Physics Homework Help
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Vector Problem -- Addition of two vectors given in polar coordinates
My bad I will comment on my lines in the future as for what I am doing I wanted to sum the two vectors, so I first needed to decompose both vectors into their component form. Then, I added these components together and then used the Pythagorean theorem to find the magnitude.- randomphysicsguy123
- Post #7
- Forum: Introductory Physics Homework Help
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Vector Problem -- Addition of two vectors given in polar coordinates
Work: x=10cos70=3.4 x=8cos45=5.65 y=10sin70=9.3 y=8sin45=5.65 x(hat)=3.4+5.65=9.05 y(hat)=9.3+5.65=14.95 R=sqrt(9.05^2+14.95^2)=17.47 R=17.47- randomphysicsguy123
- Post #5
- Forum: Introductory Physics Homework Help
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Vector Problem -- Addition of two vectors given in polar coordinates
I have made an effort however I am unsure if my first step of 10sin(70) and 8tan(45) is correct as I do not want to go off track from the start- randomphysicsguy123
- Post #3
- Forum: Introductory Physics Homework Help
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Vector Problem -- Addition of two vectors given in polar coordinates
Doing a review for my SAT Physics test and I'm practicing vectors. However, I am lost on this problem I know I need to use trigonometry to get the lengths then use c^2=a^2+b^2. But I need help going about this.- randomphysicsguy123
- Thread
- Addition Coordinates Polar Polar coordinates Vector Vectors
- Replies: 11
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
Didn't think about that. Regardless, I already turned it in and I used the equation xf=xi+vit+1/2a*t^2, which got me 15.86 meters at 3 seconds. Hope it was right. Thank you for your help.- randomphysicsguy123
- Post #11
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
1 meter- randomphysicsguy123
- Post #9
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
Yes I could however I keep getting 1m/s^2 but when xf=xi+vit+1/2a*t2 to check if that statement is true I get .92m/s^2- randomphysicsguy123
- Post #7
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
average speed=d/t a=change in v/ change in time- randomphysicsguy123
- Post #5
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
Correct. But could you provide a bit more insight as what I should do I am really lost.- randomphysicsguy123
- Post #3
- Forum: Introductory Physics Homework Help
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Projectile Motion (not on Earth)
I know I need to solve for acceleration as I am not on Earth and I am assuming I should create a distance vs. time graph. But overall I am unsure what to do. Please help been stuck on this for a while.- randomphysicsguy123
- Thread
- Earth Motion Projectile Projectile motion
- Replies: 11
- Forum: Introductory Physics Homework Help