I'm real rusty on my physics, but here are five simple sample problems we were given, I'd appreciate your help in helping me solve these. Thanks!
Homework Statement
(1) A single horizontal 10.0 N force, F acts on a 2.0 kg block which is initially at rest at x=0 m. In response to the force...
O.k. got it thanks!
the sum of the x forces is:
F-m1*a=3.4N
or
4N-(1.5kg*.367347m/s^2)=3.4N
and it is the same when you try the second mass:
F+m2*a=3.4N
or
2.2N+(3.4kg*.367347m/s^2)=3.4N
Thanks for your help.
it of course gives you force, the numbers represent my understanding of the words, I tried different combonations of adding subtracting and dividing mass, force and acceleration for the whole system but smartwork is telling me they are the wrong answers.
Homework Statement
Homework Equations
f=ma
The Attempt at a Solution
I got the acceleration by:
(f1-f2)/(m1+m2)=a
Now the first two q's I just cannot figure out.
1.5*4=nope
1.5/.367347*4=nope
1.5/.367347+4=nope
4*.367347=nope
2.66667-.647059=nope......ah!
Homework Statement
Homework Equations
F=MA
The Attempt at a Solution
Weight
M*G=55.5*9.81
Parallel force
sin(30)544.455=272.228
Perpendicular force To Plane
cos(30)544.455=471.512
Figured out that the man is pushing with a force of
tan(30)544.455=314.341N
Normal...
So AB would be straight down from initial point A? And what is the 3,4,5 triangle telling me? The proportions of PAB? If so then AB would be the 3 and PA would be the 5?
What if I just did cos(30)*10, wouldn't that give me PB? Then I could do 250*PB. But I need the perpendicular don't...
Homework Statement
Homework Equations
Torque(n/m)=Force(N)*Length(L)
Basic Trigonometry
The Attempt at a Solution
The concept of torque is new to me, so I just need a push in the right direction here. lbs and ft are used so we are using non-metric? Should I convert them to metric? How...