Recent content by Redinorun

Thank you! (I menth something like that, yes)

Thanks, got it. You're a life saver. By the way: Why wouldn't this work if a = 8cm? Is it because a would be longer than the sum of e and b (if we take half of it as a triangle)? Or is there another explanation?

I'd really need help with this. Thanks. 1. Homework Statement Draw a parallelogram: a = 4cm e + f (diagonals) = 11cm angle between a and e = 22° Homework Equations 2 and 2 sides are parallel both diagonals halve each other (diagonal e goes from A to C) The Attempt at a Solution (attachment)

Oh, right, right right! I got stuck on the pink one, for some reason I couldn't figure out that I had to gamma/2, to get the top of the yellow one. Got it now. It's very "slim". Now I know, always look for isosceles triangles and similar. Thanks again for taking the time to help me. :)

Oh, how did I not see that?! But wait... ugh... I can't figure out the angles on this one. Nor the length of a.

A picture of the problem.

"a" is one of the equal sides (just like usual). (c is the base) "h" is the height of the triangle. The angle gamma (by the point C) is given 30. So the thing also given is one of the equal sides + the height (a + h).

I actually made it. Thanks! Your pictures actually really help. The blue corner is 37,5 and the pink one is 30. At the top when the lines meet at C you just draw the same corners again, but down (because again, we have a, a and b, b) and that's it! Thanks!

Got that one. Basically after I saw your picture. I realized that both sides of your blue triangle are the same length (because b-a leaves you with a, right?) So I could calculate delta is 30, and on hand of that, that the pink marked corner is 150. That makes it fairly easy to draw the...

We didn't use any equations at school. We just drew them. :(

Hello, I would need some help with drawing these 3 triangles for my homework. Would be nice if you could just help me to start drawing (what to do first) the right way. Thanks. Homework Statement a) Regular triangle: b - a = 3cm c = 6cm γ = 120° b) Regular triangle: a + b + c = 16cm α = 75°...

Hello, I would need some help with drawing these 3 triangles which are part of my homework. Would be nice if you could just help me to at least start drawing (what to do first) the right way. Thanks. 1) Regular triangle: b - a = 3cm c = 6cm γ = 120° 2) Regular triangle: a + b + c = 16cm...

Fb = ρ * g * V1 F = Fg - Fb F = Fg - ρ*g*V1 V1 = (Fg - F) / (ρ*g) = (8,2N - 7,1N) / (1000kg/m3 * 10m/s2) = 0,00011m3 = 110cm3 V= V1 - V2 = 110cm3 - 78,8cm3 = 31,2cm3 And according to the solutions below 31,2cm3 is right! Thanks kind Sir from the internet. :)

So if I'm interpreting this right this means: Fb = ρ(water) * g Fb = 1000kg/m3 * 10m/s2 = 10000N F = Fg - Fb F = m * g - Fb m = (F + Fb) / g m = (7,1N + 10000N) / 10m/s2 = 1000,71kg V = m / ρ = 1000,71kg / 10400kg/m3 = 0,0962m3 Which is not correct... This is so hard...

ρ = 10,4 g/cm3 = 10400kg/m3 (the density of the metal) Fb = 7,10N (the weight of the metal in the water) Is this not right?