Recent content by RedPhoenix

I don't have a table handy, but how can I find \mu? I know its E(x).. or atleast I think so. I also know that the problem is written poorly and the book is not much better.

Been having an issue with these specific homework problems. Can you give me some insight on where to start. #4.78 F The actual amount of juice that a machine fills the juice boxes with is 4-ounces, which may be a random variable with normal distribution of \sigma = 0.04 ounce a) If only 2%...

I got it. 10cm < 14cm, so its inside, meaning = 0 20cm > 14cm, so ke(q/r^2) = 8.99E9(32E-9/.2^2) = 7192, so now I just have to look over where I messed up on the order of magnitude 7.192 MN/C from the center... is the answer!

Homework Statement Consider a thin spherical shell of radius 14.0 cm with a total charge of 32.0 %C distributed uniformly on its surface. Find the electric field (a) 10.0 cm and (b) 20.0 cm from the center of the charge distribution. Homework Equations The Attempt at a Solution...

Homework Statement Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.80 & 104 N/C as shown in Figure P24.4. Calculate the electric flux through (a) the vertical rectangular surface, (b) the slanted surface, and (c) the entire surface of the box...

:) Thank you for going over this problem with me. It makes a lot more sense... I think I will have another one or two tomorrow... Test at the end of this week.

Sorry I posted that from my phone, it was not the whole problem. The probability of Mark riding his bike is 0.4 Probability of Wilma riding her bike is 0.5 The probability of mark riding his bike given that Wilma does is 0.7 Find: P(M^W) both riding their bikes P(W|M) P(M or W)...

The question from the text is: Probability of Mark and Wilma both go riding a bike together.

Right. I was asked for P(m^w), I think I got it confused reading your question. so for P(m^w), I would do the P(m|w) x P(w|m) = (0.875)(0.7)=0.6125 for this question.

Interesting... I actually do not see this anywhere in my book, so can you explain why I would be using P(m|w) x P(w|m) instead of P((w|m)^(m)) ? How would I combine those terms? I don't follow, wouldn't I just multiply them?I REALLY appreciate all your help, you have no idea.

Pretty crazy, but thanks for the help :)

Thank you This is what I am understanding from the book. If they are dependent on each other, use this formula p(m^w) = p(m) x p(w | m) So... 0.875 x 0.4 = 0.35 or 0.5 x 0.7 = 0.35 Correct? ------------------- If they were independent of each other, I would multiply them...

I guess I am entirely confused. The book is making it worse and reading info online is confusing me. I am getting 2 bits of information regarding (a), which affects (c). for 1) P(MnW) = p(M) x p(W) = 0.2 but I also see 2) P(MnW) = p(M) x p(W|M) = 0.35 P(WnM) = p(w) x p(M|W) = 0.35...

Lets try this again... since I have (b) correct I will ignore it (a) p(MnW) = .4 x .5 = .2 (c) p(MuB) = .4 + .5 - .2 = .7 is this correct? sorry for not getting this, stats is not my strong point.

Another Conditional Problem... Lie Detector is 95% reliable when the person is guilty 98% reliable when innocent Random Person pulled from a pool of people... This pool is 6% guilty of theft and 94% have never stolen... Random person was determined guilty from the lie detector, what...