Recent content by RedPhoenix

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    How Do You Solve Normal Distribution Problems in Statistics Homework?

    I don't have a table handy, but how can I find \mu? I know its E(x).. or atleast I think so. I also know that the problem is written poorly and the book is not much better.
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    How Do You Solve Normal Distribution Problems in Statistics Homework?

    Been having an issue with these specific homework problems. Can you give me some insight on where to start. #4.78 F The actual amount of juice that a machine fills the juice boxes with is 4-ounces, which may be a random variable with normal distribution of \sigma = 0.04 ounce a) If only 2%...
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    Find the electrical field of a Spherical Shell

    I got it. 10cm < 14cm, so its inside, meaning = 0 20cm > 14cm, so ke(q/r^2) = 8.99E9(32E-9/.2^2) = 7192, so now I just have to look over where I messed up on the order of magnitude 7.192 MN/C from the center... is the answer!
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    Find the electrical field of a Spherical Shell

    Homework Statement Consider a thin spherical shell of radius 14.0 cm with a total charge of 32.0 %C distributed uniformly on its surface. Find the electric field (a) 10.0 cm and (b) 20.0 cm from the center of the charge distribution. Homework Equations The Attempt at a Solution...
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    Calculate Flux in a closed Triangle

    Homework Statement Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.80 & 104 N/C as shown in Figure P24.4. Calculate the electric flux through (a) the vertical rectangular surface, (b) the slanted surface, and (c) the entire surface of the box...
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    Is my Handout wrong? Stumped Conditional Probability

    :) Thank you for going over this problem with me. It makes a lot more sense... I think I will have another one or two tomorrow... Test at the end of this week.
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    Is my Handout wrong? Stumped Conditional Probability

    Sorry I posted that from my phone, it was not the whole problem. The probability of Mark riding his bike is 0.4 Probability of Wilma riding her bike is 0.5 The probability of mark riding his bike given that Wilma does is 0.7 Find: P(M^W) both riding their bikes P(W|M) P(M or W)...
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    Is my Handout wrong? Stumped Conditional Probability

    The question from the text is: Probability of Mark and Wilma both go riding a bike together.
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    Is my Handout wrong? Stumped Conditional Probability

    Right. I was asked for P(m^w), I think I got it confused reading your question. so for P(m^w), I would do the P(m|w) x P(w|m) = (0.875)(0.7)=0.6125 for this question.
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    Is my Handout wrong? Stumped Conditional Probability

    Interesting... I actually do not see this anywhere in my book, so can you explain why I would be using P(m|w) x P(w|m) instead of P((w|m)^(m)) ? How would I combine those terms? I don't follow, wouldn't I just multiply them?I REALLY appreciate all your help, you have no idea.
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    Bayes Theorem Question - Am I doing this right?

    Pretty crazy, but thanks for the help :)
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    Is my Handout wrong? Stumped Conditional Probability

    Thank you This is what I am understanding from the book. If they are dependent on each other, use this formula p(m^w) = p(m) x p(w | m) So... 0.875 x 0.4 = 0.35 or 0.5 x 0.7 = 0.35 Correct? ------------------- If they were independent of each other, I would multiply them...
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    Is my Handout wrong? Stumped Conditional Probability

    I guess I am entirely confused. The book is making it worse and reading info online is confusing me. I am getting 2 bits of information regarding (a), which affects (c). for 1) P(MnW) = p(M) x p(W) = 0.2 but I also see 2) P(MnW) = p(M) x p(W|M) = 0.35 P(WnM) = p(w) x p(M|W) = 0.35...
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    Is my Handout wrong? Stumped Conditional Probability

    Lets try this again... since I have (b) correct I will ignore it (a) p(MnW) = .4 x .5 = .2 (c) p(MuB) = .4 + .5 - .2 = .7 is this correct? sorry for not getting this, stats is not my strong point.
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    Bayes Theorem Question - Am I doing this right?

    Another Conditional Problem... Lie Detector is 95% reliable when the person is guilty 98% reliable when innocent Random Person pulled from a pool of people... This pool is 6% guilty of theft and 94% have never stolen... Random person was determined guilty from the lie detector, what...
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