Recent content by rohan03

By looking in the textbook again.

here I am attaching bitmap so jope someone can help.. word doc is problem so I will remove it

Ok. Will do.

Homework Statement a regular hexagon OPQRST has its vertices at O ( the origin) and points P,Q,R, S,T with position vector p,q,r,s,t respectively. The point U with position vector u is the midpoint of the line segment OP, and SU meets OR at the point V please see attached diagem I need...

Centre of the circle is (2,-1)in this case so if you take the point x=2 & y=-1 plug it in the y-2x<2 ten it is true. Any good?

C is not a proper subset of a as part of C lies outside A however B is a proper subset as all of b lies within A

Ehild, you lost me completely. This topic is fairly new to me so I will be happy to have bit more explanation. If you could expand or give an example that be great.

Ehild, you lost me completely. This topic is fairly new to me so I will be happy to have bit more explanation. If you could expand or give an example that be great.

So it's the area below. I thought something wasn't adding up. But as far as writing is concern. Do you have any formal way of writing this! Because I don't see how else would you write it out.

[b]1. The problem statement, A = {(x, y) belongsto R^2 : (x−2)^2 + (y + 1)^2 < 9}, B = {(x, y)belongs to R^2 : y − 2x < 2}. Show that A is a proper subset of B. The Attempt at a Solution Now I know that (x−2)^2 + (y + 1)^2 is an equation of a circle with centre translated to (2to the...

many thanks- this clarifies everything

i have typed and attached my question and my attempt here with. I am sure I know what I am doing but its a last part I am not sure about so any help would be great. Thanks

Hi May I ask what do you do? Seems like you are a teacher- so it should be pretty straightforward for you to sketch one for your student. I will have a look but chances are slim as I delete every document that I am done with.

hi this question is resolved- I have posted another question under homework section under calculus - riemann integral- can you please look at it? Thanks

that is the step I am struggling with. so by putting things in common denominator I get x/1-x now if I divide by x = why are we dividing 1/(1-x) and not x/(1-x)? or we are considering x/x + x/(1-x) = 1+ x/(1-x) and I will appreciate it if you can make further steps of part a clear as well...