Recent content by rotiff

Homework Statement Maximum current: I max = 4.62 * 10^-4 A Time constant of circuit: T = 3.9 secondsHomework Equations T= RC The Attempt at a Solution I'm trying to find the current after 1 time constant. Seems simple enough, the current changes by 63%. So (Imax)-(Imax * 0.63) or...

I figured this and thought I'd post the solution: Height at elevated position = 15 cos 32 = 12.72m Therefore h = 15-12.72 = 2.28m

has anyone got any idea, please? At this point I tried everything and I just can't get my answer to fit both a final velocity of 6.7 m/s and a reasonable height

Thank you but I still think there is some other solution that jiggles with Newton's laws. If someone figures it please post.

This is ridiculous... I'm sure the answer should be fairly easy.

I tried it and the final velocity came up as 17 m/s, I know this is wrong because in the next part it says SHOW that the final velocity just before impact = 6.7 m/s

Can you please attempt it? I have solved other parts of this question and I will see if your calculated height fits in with the rest.

I don't think so, because at the vertical position the total energy would equal kinetic energy + some potential energy therefore mgh = 0.5 mv^2 + mgh And both velocity & height are missing from the right side of the equation.

Homework Statement The Attempt at a Solution I tried to find the acceleration using F= ma Resultant force = Tension - mg so a = (10295.2-8730)/890 = 1.758 m/s^2 but I don't think it works that way... please help.