Recent content by rwishka

Homework Statement 1. A couch with a mass of 1x10^2 kg is placed on an adjustable ramp connected to a truck. As one end of the ramp is raised, the couch begins to move downward. If the couch slides down the ramp with an acceleration of 0.70 m/s^2 when the ramp angle is 25 degrees, what is...

I see. Can you help me with the other ones please?

Alright! Thanks A LOT! :) (I did get to solving the components, and got the same answer)

So would it be greater than the player's weight, as it is inversely proportional?? I think I have this all mixed up.

1. To find the third side of the triangle, I tried using the Law of Cosines. So angle A = 45 degrees, and the unknown side = a. b = 3000 and c = 6000. a^2 = b^2 + c^2 - 2bc cos 45 a^2 = 3000^2 + 6000^2 - 2 (3000)(6000) cos 45 a^2 = 45000000 - 36000000 cos 45 a = 4420.877 N So I plugged that...

Does no one know how to do these? I really need to know how soon! Please kindly help me.

1. THANKS! I got the right answer (hopefully) to be A, 2.2 m/s^2. 2. I solved that formula you gave me, and for acceleration I got a = 1.379 or 40/29. If I do free body diagram, I only know theta of 30 degrees and gravity of 9.81 m/s^2. How will that help me?

Homework Statement I promise - my last set of questions. 1. A hockey stick hits a puck on the ice. Identify an action-reaction pair, and compare the forces exerted by each object. a. The stick exerts a force on the puck; the puck exerts a force on the stick. b. The stick exerts a...

1. By the other value, I mean the third side of the triangle. Like 3000^2 + b^2 = 6000^2. 2. Which equation? final velocity = initial velocity + a(time) OR distance = initial velocity(t) + .5a(t)^2 ? For the first equation, I got -0.0068. For the second equation, I plugged in the values and got...

Homework Statement 1. A sailboat with a mass of 2.0 x 10^3 kg experiences a tidal force of 3.0 x 10^3 N directed to the east and a wind force against its sails with a magnitude of 6.0 x 10^3 N directed toward the northwest (45 degrees N of W). What is the magnitude of the resultant...

So, would it be F=80(cos 53 degrees). So F=48 N. Answer C, then? For the second question, I did 800 = cos 30 degrees (F), so F = 924 N. Answer A. Thank you SO much! :biggrin: :biggrin:

Homework Statement 1. A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 8.0 x 10^1 N is being applied to the sled rope at an angle of 53 degrees to the ground, what is the force of friction between the sled and the snow? A. 83 N B. 64 N C. 48 N D...

I checked and that is the problem. Hmm. Well, thank you for helping me! :)

Sorry, c is 75 Newtons. a = 75 N/35.0 kg a = 2.14 m/s^2 Am I missing a step? (Thanks for helping me so far)

Would I use the Pythagorean Theorem? I did (45.0)^2 + (60.0)^2 = c^2 c = 87.46 N I plugged that into a = 87.46 N/35.0 kg, and got an incorrect answer. What did I do wrong?