Recent content by Schulze

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    Mechanical energy of a spring system

    Homework Statement A damped mass-spring system oscillates at 285 Hz. The time constant of the system is 8.8 s. At t = 0 the amplitude of oscillation is 1.3 cm and the energy of the oscillating system is 36 J. Part 1: What is the amplitude of oscillation at t = 8.7 s? Answer in units of...
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    Oscillation (particle movement)

    Part 2: Determine the x coordinate of the particle acceleration at t = 1.22 s. Answer in units of m/s2 a = -w2Acos(wt + d) a = -(11 rad/s)2(4.4 m)cos((11 rad/s * 1.22 s) + 0.8511870029) a = 71.13887508 m/s2 which is correct! Thank you. But now I have more of a conceptual...
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    Oscillation (particle movement)

    Ok part 1 is correct!
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    Oscillation (particle movement)

    that's true. So if I multiply my result by 11 rad/s I get: v = -47.96598498 m/s However, is this total velocity in both x and y directions or is it the x coordinate of the velocity? I would think that it would be the x coordinate, since we are taking the derivative of the position of the x...
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    Oscillation (particle movement)

    Homework Statement A particle rotates counterclockwise in a circle of radius 4.4 m with a constant angular speed of 11 rad/s. At t = 0, the particle has an x coordinate of 2.9 m and y > 0 . Part 1: Determine the x coordinate of the particle velocity at t = 1.22 s. Answer in units of m/s...
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    Angular momentum of time dependent particle motion

    \vec{L} = \vec{r} \times m\vec{v} The angular displacement around the circle: θ = ωt = \frac{vt}{R} The vector from the center of the circle to the mass is then: Rcos(θ)i + Rsin(θ)j (in the i and j directions) The vector from the point P to the point of the mass is: \vec{r} =...
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    Angular momentum of time dependent particle motion

    That impression would be correct. A friend of mine told me the right answer but wouldn't tell me how to arrive at this result. So that that is my next aim. Answer: L = (mvR) cos((vt/R) + 1)
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    Angular Acceleration of a Fixed Rod

    Thanks for helping me out to understand the pieces of information that could be used to arrive at this answer. I did find out how to do the problem, and got the right answer! Is there any way that I mark this thread as solved?
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    Angular momentum of time dependent particle motion

    I did all those things but I thought that this site didn't want me to post a poorly drawn sketch. Furthermore, I am not very good at using Latex to make my equations look nice and bold and whatnot. Nor am I very efficient at using this yet so bare with me. Also, L2 will be in the opposite...
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    Angular momentum of time dependent particle motion

    Homework Statement A particle of mass m moves in a circle of radius R at a constant speed v. Assume: The motion begins from the point Q, which has coordinates (R, 0). Determine the angular momentum of the particle about point P, which has coordinates (−R, 0) as a function of time. The...
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    Angular Acceleration of a Fixed Rod

    @Tanya Sharma @Tanya Sharma To find the center of mass, you take the individual masses as point masses, and then calculate the center of mass between these two point masses. Xcm = [(m1)(x1)) + (m2)(x2)]/Total mass of the two objects Xcm = [(9 kg)(7 m) + (9kg)(17.2 m)] / (18 kg) Xcm = 12.1...
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    Angular Acceleration of a Fixed Rod

    Think i figured it out. Correct I: I = (Isphere + Md2) + (Irod) (Note: Irod needs no adjustment because we are rotating about a perpendicular axis through the end of the rod.) I = (2/5 (9 kg)(3.2 m)2) + (9 kg)((17.2 kg)2) + (1/3)(9 kg)(14 m)2 I≈3287.424 kgm2 Xcm= 12.1 m PEi = KEf...
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    Angular Acceleration of a Fixed Rod

    d is the distance between the two parallel axes of rotation (aka the distance between the axis of rotation Icm (of that object) and the moment of inertia I about a parallel axis through some other point). In this case, we choose that other point to be the center of mass of the two combined...
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    Angular Acceleration of a Fixed Rod

    Individual torques I quite honestly have no clue how to find, individual torques on a system composed of multiple parts.
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