Homework Statement
A damped mass-spring system oscillates at
285 Hz. The time constant of the system is
8.8 s. At t = 0 the amplitude of oscillation
is 1.3 cm and the energy of the oscillating
system is 36 J.
Part 1: What is the amplitude of oscillation at t =
8.7 s?
Answer in units of...
Part 2: Determine the x coordinate of the particle acceleration
at t = 1.22 s.
Answer in units of m/s2
a = -w2Acos(wt + d)
a = -(11 rad/s)2(4.4 m)cos((11 rad/s * 1.22 s) + 0.8511870029)
a = 71.13887508 m/s2
which is correct!
Thank you.
But now I have more of a conceptual...
that's true. So if I multiply my result by 11 rad/s I get:
v = -47.96598498 m/s
However, is this total velocity in both x and y directions or is it the x coordinate of the velocity?
I would think that it would be the x coordinate, since we are taking the derivative of the position of the x...
Homework Statement
A particle rotates counterclockwise in a circle
of radius 4.4 m with a constant angular speed
of 11 rad/s. At t = 0, the particle has an x
coordinate of 2.9 m and y > 0 .
Part 1: Determine the x coordinate of the particle velocity
at t = 1.22 s.
Answer in units of m/s...
\vec{L} = \vec{r} \times m\vec{v}
The angular displacement around the circle:
θ = ωt = \frac{vt}{R}
The vector from the center of the circle to the mass is then:
Rcos(θ)i + Rsin(θ)j (in the i and j directions)
The vector from the point P to the point of the mass is:
\vec{r} =...
That impression would be correct.
A friend of mine told me the right answer but wouldn't tell me how to arrive at this result. So that that is my next aim.
Answer: L = (mvR) cos((vt/R) + 1)
Thanks for helping me out to understand the pieces of information that could be used to arrive at this answer.
I did find out how to do the problem, and got the right answer!
Is there any way that I mark this thread as solved?
I did all those things but I thought that this site didn't want me to post a poorly drawn sketch. Furthermore, I am not very good at using Latex to make my equations look nice and bold and whatnot.
Nor am I very efficient at using this yet so bare with me.
Also, L2 will be in the opposite...
Homework Statement
A particle of mass m moves in a circle of
radius R at a constant speed v. Assume: The
motion begins from the point Q, which has
coordinates (R, 0).
Determine the angular momentum of the
particle about point P, which has coordinates
(−R, 0) as a function of time.
The...
@Tanya Sharma
@Tanya Sharma
To find the center of mass, you take the individual masses as point masses, and then calculate the center of mass between these two point masses.
Xcm = [(m1)(x1)) + (m2)(x2)]/Total mass of the two objects
Xcm = [(9 kg)(7 m) + (9kg)(17.2 m)] / (18 kg)
Xcm = 12.1...
Think i figured it out.
Correct I:
I = (Isphere + Md2) + (Irod) (Note: Irod needs no adjustment because we are rotating about a perpendicular axis through the end of the rod.)
I = (2/5 (9 kg)(3.2 m)2) + (9 kg)((17.2 kg)2) + (1/3)(9 kg)(14 m)2
I≈3287.424 kgm2
Xcm= 12.1 m
PEi = KEf...
d is the distance between the two parallel axes of rotation (aka the distance between the axis of rotation Icm (of that object) and the moment of inertia I about a parallel axis through some other point).
In this case, we choose that other point to be the center of mass of the two combined...