Recent content by Seraph404

Haha. I apologize. The question I asked was actually very simple compared to the other topics being posted in this forum. The link you sent me looks like cases in which you would use trig substitution (though, that doesn't seem to be how the problems are worked out). But in the problem above...

Homework Statement x = 1+3t^2 y=3+2t^3 0<= x <=4 Homework Equations L = integral from a to b of \sqrt{[dx/dt]^2 + [dy/dt]^2} dx The Attempt at a Solution dx/dt = 6t dy/dt = 6t^2 L = integral from 0 to 4 of \sqrt{(6t)^2 +(6t^2)^2} dx = " \sqrt{36t^2 +36t^4} dx = "...

I looked up on google what MeV stood for and I saw that it was 1 electron volt times a million. Maybe my source was wrong *shrug*. So is b significant at all in finding the closest distance that the alpha particle comes to the lead nucleus?

So far is this the correct setup? L1 = L2 P0b = p(Rmin) [Rmin is the minimum distance the two particles get to each other] v0b=vf(Rmin) [mass doesn't change so I canceled it] K0+U0 = Kf+Uf K0 = .5mV0^2 = 1 mil(1.602E-19) J [ I can use this to find initial velocity, assuming that I can use...

So then it's just approaching at an angle then? That's the only difference between this and what I described?

Wait... does the alpha particle cause the lead nucleus to rotate?

Homework Statement An alpha particle with kinetic energy 10.5 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L = p_0 b, where p_0 is the...

Nevermind. I think I just need to clear the memory out the memory in my calculator. Thanks a lot!

So... S = 2\pirh ES = \lambda*h/\epsilon0 E(r) = \lambda*h/(\epsilon02\pirh) h cancles... E(r) = \lambda/(\epsilon02\pir) And now... v = \int E(r) * dr Is that right?

Is \intdl the distance from the surface of the insulating cylinder to the point at which I'm measuring potential? I'm guessing not because I'm totally not getting the right answer.

Homework Statement A long, insulating cylindrical shell of radius .06 m carries a linear charge density of 8.5E-6 C spread uniformly over its outer surface. What would a voltmeter read if it were connected between the surface of the cylinder and .04 m above the surface? Homework Equations...

Homework Statement A spherical tank is full of water. If radius r = 3m and height h = 1.5m, find the work W required to pump the water out of the spout. (Use 9.8 for g and 3.14 \pi)Homework Equations Work is the integral from a to b of f(x)dx. The Attempt at a Solution Volume= area *...

Homework Statement E1 = 2.9E4 N/C E2 = 8.6E4 N/C Both fields are uniform Homework Equations flux = \int Eperp*dA = Qencl/ \epsilon0 The Attempt at a Solution flux1 = E1cos(30)(.05m)(.06m) flux2=E2cos(30)(.05m)(.06m) (flux1+flux2) = Qencl/ \epsilon0 Homework...

Okay, I changed the problem.

Homework Statement Two very large, nonconducting plastic sheets, each 10.0 cm thick, carry uniform charge densities \sigma1, \sigma2, \sigma3, & \sigma4 on their surfaces, as shown in the figure . These surface charge densities have the values \sigma1= -6.00E-6 C/m^2, \sigma2=...