# Electric Field: not quite getting the correct answer

• Seraph404
In summary, an electric field is a physical quantity that describes the force experienced by a charged particle in the presence of other charged particles. It is calculated by dividing the force exerted on a test charge by the magnitude of the test charge or by using Coulomb's Law. The unit of electric field is Newtons per Coulomb (N/C) in the SI system and dynes per statcoulomb (dyn/statC) in the CGS system. The electric field affects charged particles by exerting a force on them, causing them to accelerate, decelerate, or change direction. Electric potential is a scalar quantity that describes the potential energy of a charged particle, while electric field is a vector quantity that describes the force experienced by
Seraph404

## Homework Statement

E1 = 2.9E4 N/C
E2 = 8.6E4 N/C
Both fields are uniform

## Homework Equations

flux = $$\int$$ Eperp*dA = Qencl/ $$\epsilon$$0

## The Attempt at a Solution

flux1 = E1cos(30)(.05m)(.06m)
flux2=E2cos(30)(.05m)(.06m)
(flux1+flux2) = Qencl/ $$\epsilon$$0

## Homework Statement

But my answer is wrong. I appreciate any help.

What is the question?

Also, those fields are at an angle of 60 degrees from the surface normal.

It looks like you have the right approach by using the equation for electric flux, but there might be a small error in your calculations. Make sure you are using the correct values for the angles (30 degrees) and the area (.05m x .06m). Also, double check your units to make sure they are consistent. If you are still having trouble, try breaking down the problem into smaller steps and double check each step to see where the error might be. Keep in mind that the electric field is a vector quantity, so make sure you are taking into account the direction of the field when calculating the flux. If you are still having difficulty, don't hesitate to reach out to your instructor or classmates for clarification. Good luck!

## 1. What is an electric field?

An electric field is a physical quantity that describes the force experienced by a charged particle in the presence of other charged particles. It is a vector field, meaning it has both magnitude and direction.

## 2. How is an electric field calculated?

The electric field is calculated by dividing the force exerted on a test charge by the magnitude of the test charge. It can also be calculated using Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

## 3. What is the unit of electric field?

The unit of electric field is Newtons per Coulomb (N/C) in the SI system of units. In the CGS system, the unit is dynes per statcoulomb (dyn/statC).

## 4. How does the electric field affect charged particles?

The electric field exerts a force on charged particles, causing them to accelerate or decelerate depending on the direction of the field. The field can also cause charged particles to change their direction of motion.

## 5. What is the difference between electric field and electric potential?

Electric potential is a scalar quantity that describes the potential energy of a charged particle in an electric field. Electric field, on the other hand, is a vector quantity that describes the force experienced by a charged particle in an electric field. In other words, electric potential is the potential energy per unit charge, while electric field is the force per unit charge.

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