Electric Field: not quite getting the correct answer

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SUMMARY

The discussion focuses on calculating the electric flux through a surface subjected to two uniform electric fields, E1 = 2.9E4 N/C and E2 = 8.6E4 N/C, both at an angle of 60 degrees from the surface normal. The user attempted to compute the total electric flux using the formula flux = ∫ Eperp * dA = Qencl / ε0, but reported an incorrect answer. The calculations for flux1 and flux2 were performed using the cosine of 30 degrees, which is incorrect given the angle of incidence.

PREREQUISITES
  • Understanding of electric field concepts and units (N/C)
  • Familiarity with the concept of electric flux
  • Knowledge of the integral calculus involved in flux calculations
  • Proficiency in using trigonometric functions for angle adjustments
NEXT STEPS
  • Review the calculation of electric flux with respect to angles using the correct cosine value.
  • Study the implications of uniform electric fields on flux calculations.
  • Learn about Gauss's Law and its application in electric field problems.
  • Explore the effects of surface orientation on electric flux through different geometries.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in solving electric field problems in academic settings.

Seraph404
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Homework Statement



YF-22-35.jpg


E1 = 2.9E4 N/C
E2 = 8.6E4 N/C
Both fields are uniform

Homework Equations



flux = [tex]\int[/tex] Eperp*dA = Qencl/ [tex]\epsilon[/tex]0


The Attempt at a Solution





flux1 = E1cos(30)(.05m)(.06m)
flux2=E2cos(30)(.05m)(.06m)
(flux1+flux2) = Qencl/ [tex]\epsilon[/tex]0

Homework Statement



But my answer is wrong. I appreciate any help.
 
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What is the question?

Also, those fields are at an angle of 60 degrees from the surface normal.
 

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