I apologize in advance if some of my answers don't quite make sense. I'm generally articulate, but not when it comes to physics I'm barely grasping.
I did a lab and part of it was dropping a magnet through a coil, which produced a Voltage vs Time graph using LabPro. For trial 1 we had the N...
A moving proton has 6.4x10^-16 J of kinetic energy. The proton is accelerated by a potential difference of 5000 V between parallel plates.
The proton emerges from the parallel plates with what...
Thanks for the help. Not sure I followed it all exactly, and it was long past when it had to be handed in. I kind of gave him two papers and told him, "Take this one, no this one, wait, maybe this one" and he just took both so we'll see what happens. I don't know why my grasp of vectors is...
Ok so I found the difference in momentum for ball 1(.400kg) is 0.280kg m/s. Then I used that to find that ball 2's velocity is that divided by the mass (.500kg) to get 0.560m/s. Now I just need the direction. I know in a different question we assumed the y components were the same, so can I...
Yes I used the squared 0.500kg. Should I be using the 30, 60, 90 triangle made by the x and y components of the momentum of the .400kg ball?
I'm not sure how to use ball 1 to figure out ball 2's(the heavier one) direction.
This is all I have. Some one please please pleeeeeaaaase check this over and see if I'm in any way on the right track. I haven't had much sleep the past few days and am really stressing over my courses. This is a take home part of our unit test. I hope I did this right because it could really...
A small explosive device slicing to the right breaks into two pieces. The momentum of fragment 1 after the explosion is 23kg.m/s 28°RCS
What is the momentum of fragment 2 after the explosion?
A mass moves in a circular path that has a radius of 24.6cm on a horizontal frictionaless surface. If the centripetal force acting on the mass is 96.5N, what is the kinetic energy of the mass?
He told us to use these and "play...
A physics student slides a 2.0kg textbook along the laboratory bench to her friend. She imparts to the book an initial velocity of 2.70m/s. μ=0.20. How far away is her friend if the book comes to a stop right in front of her friend
Vi= 2.70m/s μ=0.20 m=2.0kg Vf= 0m/s...
I'm not having problems with the others, just when I need to find a mass with minimal info.
Use the total mass of the system. The difference of force of gravity and tension on the rope would be the net force acting on the system.