http://in.answers.yahoo.com/question/index?qid=20080111225452AADKNLv
I was told that
tan(a/2)tan(b/2)+tan(a/2)tan(c/2)+tan(b/2)tan(c/2) =1 is useful.
You can prove that by taking the tan of both sides of the following
(a+b)/2 = 90 -c
Thanks for trying.
Thanks SammyS.
Since a + b + c = π we can prove that (cot A)(cot B)(cot C) = cot A + cot B + cot C
With that I did the following.
Rearrange given equation:
2[tan(a/2) + tan(b/2) + tan(c/2)] < [tan(a/2) * tan(b/2) * tan(c/2)]^-1
2[tan(a/2) + tan(b/2) + tan(c/2)] < cot(a/2) * cot(b/2) * cot...
Homework Statement
Show that the angles a, b, c of each triangle satisfy this inequality.
\tan \frac{a}{2}\tan \frac{b}{2} \tan \frac{c}{2} (\tan \frac{a}{2} + \tan \frac{b}{2} + \tan \frac{c}{2}) < \frac{1}{2}
Homework Equations
The Attempt at a Solution
I used the half angle...
This is exactly how I started working on it but then I got stuck. I ended up solving it a different way. I expanded the whole expression on a common denominator (abc). Then I factored the numerator into −(a−b)(a−c)(b−c) (See https://www.physicsforums.com/showthread.php?t=643010)
Then I used...
Homework Statement
This question stems from this one: https://www.physicsforums.com/showthread.php?t=642712
I think I know how to solve it now. The only problem is I have to show how to factor this expression into the form WolframAlpha shows.
-a^2 b + a b^2 + a^2 c - b^2 c - a c^2 + b...
I've done all the trig usually done at the high school level. My analytic geometry skills aren't that good though.
Can someone please help me? I need to solve this for tomorrow. I've been working on it for like 5 hours and I'm still stuck.
Homework Statement
Prove the following inequality for any triangle that has sides a, b, and c.
-1<\frac{a}{b}+\frac{b}{c}+\frac{c}{a}-\frac{b}{a}-\frac{a}{c}-\frac{c}{b}<1
Homework Equations
The Attempt at a Solution
I think we have to use sine or cosine at a certain point because...
Homework Statement
Prove the following inequality for any triangle that has sides a, b, and c.
-1<\frac{a}{b}+\frac{b}{c}+\frac{c}{a}-\frac{b}{a}-\frac{a}{c}-\frac{c}{b}<1
Homework Equations
The Attempt at a Solution
I think we have to use sine or cosine at a certain point because...
That's true! Thanks. So if I did it correctly this what I got for a 1 x 10 rectangle. (For simplicity, rectangle refers to 1x3 and square refers to 1x1)0 rectangles and 10 squares: 1
1 rectangle and 7 squares: 8
2 rectangle and 4 squares: 15
3 rectangle and 1 squares: 4Total = 28 ways to cover a...