How's this...
E \Psi(x,t) = i\hbar \frac{\partial}{\partial t} \Psi(x,t), \Rightarrow E \Psi^*(x,t) = -i\hbar \frac{\partial}{\partial t} \Psi^*(x,t)
Giving:
\frac{\partial \Psi}{\partial t} = -\frac{iE}{\hbar} \Psi(x,t) and \frac{\partial \Psi^*}{\partial t} = \frac{iE}{\hbar}...