Recent content by Sir James

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    Fundamental Theorem of Calculus - Variables x and t

    Thanks for the responses Verty, HallsofIvy and Paulfr
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    Fundamental Theorem of Calculus - Variables x and t

    Hello, I'm getting slightly confused by the following so was hoping someone may be able to clear my problem up. For integrals, if b is the upper limit and a is the lower limit, I will write ∫[b,a]. From the Fundamental Theorem of calculus part 1 we can show that: if F(x) = ∫[x,a]...
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    Question re. the Pressure Energy of a Fluid

    Much appreciated Chet, I was going wrong by not looking at the hydraulic gradient as a vector. This meant I didn't understand why the length L was sometimes measured horizontally, sometimes vertically or sometimes in the direction of flow. I now see that this just depends on the direction of the...
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    Question re. the Pressure Energy of a Fluid

    In that case Chestermiller I do have another question. I am trying to get my head around the equation for the velocity of flow through a soil. The equation is: V = Ki Where: V = velocity K = Darcy coefficient of permeability i = Hydraulic Gradient = (head at point 1-head at point 0/horizontal...
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    Question re. the Pressure Energy of a Fluid

    Tiny-Tim and Chestermiller thanks very much, your answers have helped me to clear up what I was confused over. I'm looking at this in relation to permeability values of soil so need to get it right before I bring in the Darcy Coefficient.
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    Question re. the Pressure Energy of a Fluid

    Hello Tiny Tim, thanks very much. I'm still a little lost with this one though. In Understanding Hydraulics (Hamill, 2011) it states that the pressure energy per unit weight of a fluid is equal to the height of the head. Then total energy indicated by a head is: head * weight which can also...
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    Question re. the Pressure Energy of a Fluid

    I’m confused as to how energy per unit weight can be quantified as a head of fluid. I have tried to understand this from a couple of angles but am getting confused. I’ll go through my methodology to see where you can spot the cracks. If energy = work done = (force * length over which it acts)...
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