Recent content by sktgurl930

ok i solved for w and i was going to put it into the other equation u gave me for A but i don't kno which V or X to put in for it

Homework Statement A 284 g oscillator has a speed of 94.86 cm/s when its displacement is 2.98 cm and 74.06 cm/s when its displacement is 5.92 cm. What is the oscillator's maximum speed? Homework Equations Vmax=2pi*f*A The Attempt at a Solution confused as to wat the AMP would be

so my mass 1 is the ball not moving right?? is this the equation i use to get the answer or do i have to plug it into another one

Homework Statement A 15 g ball is fired horizontally with speed v0 toward a 117 g ball hanging motionless from a 1.53-m-long string. The balls undergo a head-on, perfectly elastic collision, after which the 117 g ball swings out to a maximum angle θmax=53°. What was v0? Homework Equations...

thank u it makes sense now

I try but it doesn't work out am i missing something? is it positive or negative ?? i was thinking its negative goes its going down

Homework Statement The two ropes are used to lower a 267.18 kg piano 5.34 m from a second-story window to the ground. How much work is done by gravity force? (T1=1864 N, θ1=64°, T2=1231 N, θ2=50°.) How much work is done by T1 force? How much work is done by T2 force? Homework Equations...

im sry for asking this but y did u times 6.64 by 804.53?? and then add the two answer

Homework Statement A computer hard disk starts from rest, then speeds up with an angular acceleration of 198 rad/s2 until it reaches its final angular speed of 7683 rpm. How many revolutions has the disk made 10.7 s after it starts up? Homework Equations t=wf/a delta0=wi*t+(1/2)(a)t^2...

ok so this is wat i got ignore the last post wx=M*gsin = 8.324N Fk= Mk*N = 3.9396 N Fk-Wx/m= - 4.385 m/s^2 Xf=xi+(Vf^2-Vi^2/2a)= 9.133 Xf*sin= 3.8599 would this be my height?

ok so i think i drew it right and this is the equation i got from it fnetx= -Fk-Wsin+v=Ma fnety=N-Wcos=Ma how does that give me height and accerelation

Homework Statement A 2.8 kg wood block is launched up a wooden ramp that is inclined at a 34° angle. The block’s initial speed is 8.56 m/s. What vertical height does the block reach above its starting point? What speed does it have when it slides back down to its starting point...

thank u and i wish u were my teacher dude ur a life saver!

im not going to lie I am teacher isn't very good at teaching so i have no idea wat ur talkin about with x and y please don't hate me

ok so would the angles be 17 since they are equal angles?? and i got 17 by making a right triangle with 3.91 being the hypotenuse, and since the speaker is 1.15m away from the ceiling making that one of the sides of the triangle with the right angle. im i right?? or totally off