Recent content by Sneakatone

sorry for the late reply but I found that the released spring distance was in inches so I just had to convert the 15 into ft.

From the looks of this does amplitude not matter , only the period?

Homework Statement I do not know how to find f(t) with the given Ampliture 40 and a=pi Homework EquationsThe Attempt at a Solution I have the solution above. my set up was 1/2y''+y'+5=f(t) 1/2S^2* Y(s) + Y(s)+5=f(t)

my answer came out to be y(x) = -6/5 e^(-7 x/2) (7 sqrt(15) sin((sqrt(15) x)/2)+15 cos((sqrt(15) x)/2)) which is different. and yes the problem is suppose to be released at 18 not 15.

my answer came out to be y(x) = -6/5 e^(-7 x/2) (7 sqrt(15) sin((sqrt(15) x)/2)+15 cos((sqrt(15) x)/2)) which is different and yes the problem is suppose to be released at 18 not 15.

Homework Statement A 4-pound weight stretches a spring 2 feet. The weight is released from rest 15 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to 7/8 times the instantaneous velocity. Use the Laplace...

so an equation like v=1xt i + 2xt j +6xt k would be 3d but V= 1xt i +6x j+7 k wouldbe 1D?

can c2 be -cot(x) ? or can I put any number and it will be correct?

so can I say c2=0 making: y=e^x cosx ?

Homework Statement The given two-parameter family is a solution of the indicated differential equation on the interval (−infinity, infinity). Determine whether a member of the family can be found that satisfies the boundary conditions. (If yes, enter the solution. If an answer does not exist...

I see now, I had slightly the wrong equation. I used the one for population instead. I solved for k=ln(2)/5730 then did A(660)=e^(-ln(2)/5730*660) = .92 => 92%. thanks alot!

Homework Statement The Shroud of Turin, which shows the negative image of the body of a man who appears to have been crucified, is believed by many to be the burial shroud of Jesus of Nazareth. See the figure below. In 1988 the Vatican granted permission to have the shroud carbon-dated. Three...

sorry for not being clear in the picture A,B,C are just node indicators for the resistors. 0.0617, 0.025, 0.041 Are the amp measurements in the specified resistor .

sorry I for got my photo , I added what I tried but I am still lost.

Homework Statement uploaded is the circuit with resistors technically in series. R1 had a measured value of 160 ohms (from A to B) 0.0617 Amps R2 had a measured value of 387 ohms (from B to C) 0.025 amps from A to C the resistance measured is 243.9 ohms 0.041 amps this means that there is a...