Hi HallsofIvy!
like say you insert some data points and then use your calculator to calculate the linear regression. the calculator spits out
y=0.0283x+0.0012, r2=0.998
so the r2 is the coefficient of determination
A text says that if you calculate the linear regression of data points and you get the equation y=mx+b with an r2 value, the error in the slope is given by:
δm/m=2(1-r)
No explanation was given. Could someone please explain this formula? Thanks!
Attached is the formula for the equation of motion for a system of coupled oscillators.
Could someone please tell me what the variables and indices refer to here?
Thanks! :)
Thanks tiny-tim! :D
I think the line you quoted was not my question however;
we need vi2cos2(θ)/2g = gR2/2vi2
but this leads to cos2(θ) = sin2(2θ) which is not an equality.
Thanks again!
Thanks! could you please explain further how you know this to be true?
If you look here: http://en.wikipedia.org/wiki/Trajectory#Range_and_height
I'm assuming x is the max range R?
Then y = vi2sin2(θ)/2g = vi2/2g * (1 - cos2(θ))
Now if this were to match the equation in OP, then we need...
Where did this equation come from? (attached)
I can only think of the equation for d found at the end of the section in this wikipedia article: http://en.wikipedia.org/wiki/Range_of_a_projectile#Flat_ground
Thanks!
By length contraction, ship A thinks B is a distance 2.52x10^12/√(1-0.8^2) away
thus the time is 2.52x10^12/√(1-0.8^2) / (0.946c) = 14799... still not right :(
By the way, I know how to solve this problem by first calculating the time of collision as seen from the Earth. I just want to know how to calculate it using distances and speeds from the point of view of the rockets as well.
Hello physics forums people, could you please help me?
Homework Statement
According to an Earth observer, rocket 1 has speed 0.800c, rocket 2 has speed 0.600 c and rockets are initially 2.52x10^12 m apart. The rockets are approaching each other.
According to each Rocket, how long is it...