Recent content by SoccaCrazy24

ok well I am looking at this problem and i see confused... and I am trying to work it out myself... so what you are saying is that... 2f_open and 1.5f_open beat the same as 9f_open and 8.5f_open?

Well in order to do this... you must use volume expansion since it is not a rod gaining length... so you must use the equation... (delta)V = 3*alpha*V*(delta)T and for (delta)V you can substitute in V1-V2 and remember that you must have it in raidus and not diameter when finding (delta)V so...

not to be repetitve or a forum whore? but does anyone have a clue?

Question 1: A hole in an aluminum plate has a diameter or 1.178 cm at 23.00 degrees Celsius. (A) What is the diameter of the hole at 199.0 degrees Celsius? (B) What temperature is the diameter of the hole equal to 1.176 cm? For (A) I used the equation Change in Area = 2 * alpha * A *...

density with calculus? here is the problem.. A round wooden log with a diameter of 71 cm floats with 27% of its radius out of the water. What is the log's density? Yes my friend found the answer using integrals... I believe it was 919 kg/m3 roughly... but is there possibly an easier way of...

A patient is given an injection with a hypodermic needle 3.2 cm long and 0.25 mm in diameter. Assuming the solution being injected has the same density and viscosity as water at 20°C, find the pressure difference needed to inject the solution at the rate of 1.5 g/s. ok I have the equation V =...

well if anyone else can help please feel free... I am a little bit lost on this one...

ok well... kilo means thousand so you don't divide bya 1000... you multiply by a thousand... and you also have to remember there are 4 tires supporting a car so you have to account for all 4 tires... but I am unsure of whether you converted your area correctly because its squared... so you can't...

umm no... but there is a problem with similar numbers that vary maybe by a little bit such as a height of 1.4 m and diameter of 4.8 m I am not sure... but the answer was 160 kN ... i can get you the information for the problem that comes out to be 160 kN tomorrow...

for 1) kPa = Kilo Pascal Pascal = 1 Newton/meter^2 so you have your pressure in N/m^2 and your area is in cm^2 so you can easily change area from cm^2 to m^2

well in the problem it does not say any liquid is in there so the only fluid i can think of is the atmospheric pressure or pressure of air which is 101000 N/m2 ... is this right?

An above-ground backyard swimming pool is shaped like a large hockey puck, with a circular bottom and a vertical wall forming its perimeter. The diameter of the pool is 4.9 m and its depth is 1.3 m. Find the total outward force exerted on the vertical wall of the pool. so P= F / A and i used...

Question 1: If a projectile is launched from Earth with a speed equal to the escape speed, how high above the Earth's surface is it when its speed is 96% of the escape speed? On this question i understand i am not finding how high it would go if it were launched at 96% of the escape velocity...

so you are saying a =w^2 * r... so w = sqroot(a/r) so w= sqroot(.023037/5000) = .0021465 ?

Consider a spherical asteroid with a radius of 5 km and a mass of 8.65x10^15 kg. (a) What is the acceleration of gravity on the surface of this asteroid? ANSWER: ___ m/s2 (b) Suppose the asteroid spins about an axis through its center, like the Earth, with an angular speed . What is the...