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Now the solution for b) We have the following equations Critical Damping Coefficient cc = 2√km = 2mωn f = ωn / 2*(pi) ωn = √k/m cc = 2√km z = c/cc ωd = ωn√(1-z2) Therefore we can get ωn = √k/m = √30*103/5 = 77.45 rad/s And from above equations we can derive that...

Here is the solution for part a, its just that we have to take into consideration that r > √2 otherwise no isolation a) For isolation to happen r > √2 Now r = ω/ωn Now forced frequency ω = 2(pi)f = 2*pi*30 = 188.49 rad/s so for r > √2 ω/ωn > √2 ω/√2 > ωn as ω =188.49...

Spring Mass Damping System Question?? Maximum acceleration?? Homework Statement Hello, I was wondering if anyone knows how to go about answering these type of questions... Anti-vibration mounts are used to attach an instrument of mass 5kg to a panel. The panel is vibrating with an...