Now the solution for b)
We have the following equations
Critical Damping Coefficient cc = 2√km = 2mωn
f = ωn / 2*(pi)
ωn = √k/m
cc = 2√km
z = c/cc
ωd = ωn√(1-z2)
Therefore we can get
ωn = √k/m = √30*103/5 = 77.45 rad/s
And from above equations we can derive that...
Here is the solution for part a, its just that we have to take into consideration that r > √2 otherwise no isolation
a) For isolation to happen r > √2
Now r = ω/ωn
Now forced frequency ω = 2(pi)f = 2*pi*30 = 188.49 rad/s
so for r > √2
ω/ωn > √2
ω/√2 > ωn as ω =188.49...
Spring Mass Damping System Question?? Maximum acceleration??
Homework Statement
Hello,
I was wondering if anyone knows how to go about answering these type of questions...
Anti-vibration mounts are used to attach an instrument of mass 5kg to a panel. The panel is vibrating with an...