Recent content by spdowind
-
S
What Is the Angular Velocity of a Complex Rigid Body Assembly?
Idisk= 1/2 ( MR^2) = (1/2) ( 15) (0.4) (0.4)= 1.2 Irod= 1/12 ( ML^2)+ Md^2= 1/12 (8)(1.2)(1.2)+ 8(0.2)(0.2)= 1.28 Isphere= MR^2= 4 ( 0.8)^2 = NOT 3.2 I see haha thanks so much man I knew i messed up one place, i forgot to square the R for Inertia for sphere.- spdowind
- Post #3
- Forum: Introductory Physics Homework Help
-
S
What Is the Angular Velocity of a Complex Rigid Body Assembly?
Homework Statement The rigid body assembly is made from a 15 Kg disk, an 8 Kg slender rod, and a small 4 Kg sphere. The radius of the disk is R = 0.4 m and the length of the rod is L = 1.2 m. The pivot O is at the center of the disk. The assembly is released from rest at the horizontal...- spdowind
- Thread
- Body Dynamics Rigid body Rigid body dynamics
- Replies: 2
- Forum: Introductory Physics Homework Help
-
S
Right hand rule finding torque help
Homework Statement It is part of a question, i am not sure how to use RHR to find direction. http://img220.imageshack.us/img220/2594/rhr.jpg Uploaded with ImageShack.us I need to find direction of torque by using right hand rule with the Force vector and R vector ( pointing away from pivot...- spdowind
- Thread
- hand Right hand rule Torque
- Replies: 1
- Forum: Introductory Physics Homework Help
-
S
Two blocks sliding and the collision
I tried it again with cleaner procedures and found that it should be sqrt 14.7. However, I forgot to make V1 negative this time. Good thing I checked this and with your help I changed V1 to negative and guess what, I finally found the correct answer. Thank you so much! This was the only one...- spdowind
- Post #3
- Forum: Introductory Physics Homework Help
-
S
Two blocks sliding and the collision
Homework Statement Two blocks are on a frictionless track with a vertical, quarter circle, and 30 degree incline. Released from rest at point A, 1 kg smaller block 1 slides to B and makes an inelastic collision with 5 kg stationary larger block 2. The collision sents block 2 up the ramp. The...- spdowind
- Thread
- Blocks Collision Sliding Two blocks
- Replies: 2
- Forum: Introductory Physics Homework Help
-
S
Weight Component: Find Force Components for Box on Inclined Surface
well from my understand again,my graph is a lil off the angle is wrong. What I do understand is: The weight is split into 2 components like my graph, but one is horizontal to the sliding surface , one is perpendicular to it, the one horizontal is the X compoent, which means parallel to surface...- spdowind
- Post #4
- Forum: Introductory Physics Homework Help
-
S
Weight Component: Find Force Components for Box on Inclined Surface
See i am trying to find the horizontal forces for the block sliding down. I did: Fx= m* ax mg*sin(angle)- Tension force - Friction Force= mass * Acceleration. I just don't understand why I use mg* sin ( angle) instead of mg*cos(angle) when I do the weight x-component minus tension force...- spdowind
- Post #3
- Forum: Introductory Physics Homework Help
-
S
Weight Component: Find Force Components for Box on Inclined Surface
Homework Statement Well I am trying to get help on weight compent. It is a box sliding on an inclined surface with angle 30 degrees. Homework Equations w= mg The Attempt at a Solution I am trying to find the components for weight force acting on the box. Book says w=mgcos(30) is...- spdowind
- Thread
- Component Weight
- Replies: 3
- Forum: Introductory Physics Homework Help