Recent content by sprinter08

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    Friction and Acceleration: Solving a Rope Pulling Problem

    Thank you. Now I see how to get the answer.
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    Friction and Acceleration: Solving a Rope Pulling Problem

    Thank you for your explanation. It did help me to better understand the concepts. However, I am still confused as to how I got the number 71.5 in the equation, 168N-71.5/35 kg=a. I did something and did not write it down and can not remember what formula I used.
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    Friction and Acceleration: Solving a Rope Pulling Problem

    Homework Statement A student pulls on a rope attached to a box of books and moves the box down the hall. The student pulls with a force of 185N at an angle of 25.0 degrees above the horizontal. The box has a mass of 35.0kg and a mu between the box and the floor is 0.27. Find the acceleration...
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    Find the coefficient of static friction

    so would I take 165 and multiply it by the weight of the chair (25 kg) to find static friction and multiply 127 by 25 to find kinetic friction?
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    Find the coefficient of static friction

    Homework Statement A 25kg chair initially at rest on a horizontal floor requires a 165N horizontal force to set it in motion. Once the chair is in motion, a 127N horizontal force keeps it moving at a constant velocity. a.) Find the coefficient of static friction between the chair and the...
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    When Does the Package Reach the Ground?

    Homework Statement A helicopter is ascending vertically with a speed of 5.5m/s. At a height of 100m above the Earth, a package is dropped from a window. How much time does it take the package to reach the ground? Homework Equations delta y = Vot + 1/2at^2 The Attempt at a Solution...
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    Vertical Kinematics: Solving for Jump Time

    well, I was just wondering if I were to take the square of the top and then divide it by the bottom, or if I divided the top by the bottom and then took the square root. I divided the top by the bottom, and then took the square root to get .57. But then I think I would need to multiply it by 2...
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    Vertical Kinematics: Solving for Jump Time

    Oh, sorry, I misread your question I think. I'm not sure if I know how to figure that out.
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    Vertical Kinematics: Solving for Jump Time

    Vo in this case would be zero, I believe...and if it would be zero, then it would eliminate the first part of the equation (Vot).
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    Vertical Kinematics: Solving for Jump Time

    Homework Statement A kangaroo jumps to a vertical height of 2.8m. How long was it in the air before returning to Earth? Homework Equations delta y= Vot + 1/2at^2 The Attempt at a Solution I had to get t by itself so I rearranged the equation to say: t= delta y/.5(9.8) all under...
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    Sprint Acceleration and Time to Top Speed Calculation

    Homework Statement A world-class sprinter can burst out of the blocks to essentially top speed (of about 11.5m/s) in the first 15.0m of the race. a.) What is the average acceleration of this sprinter? b.) How long does it take her to reach that speed? Homework Equations The...
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    Acceleration of Sports Car: Solve Problem

    Thank you. That makes sense to me now.
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    Acceleration of Sports Car: Solve Problem

    I'm not sure if I exactly understand. I understand a little more than I did before. It is hard for me because my class does not use a book and we have one practice problem as our notes.
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