Recent content by stardust006
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Equivalent Resistance: Simplifying Circuits with Symmetry
[FONT="Arial"][SIZE="3"] how can i solve the equivalent resistance? I assume R = 2 and I = 3, I know I in node A will be divided. It's just that I don't know what direction I will go to solve for Voltage so I can solve the equivalent resistance. Is Req = 4/3 Ω ? on[/b]- stardust006
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- Equivalent Equivalent resistance Resistance
- Replies: 2
- Forum: Introductory Physics Homework Help
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Finding the volume of the solid generated by revolving the area
Ok, thanks again! :)- stardust006
- Post #8
- Forum: Calculus and Beyond Homework Help
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Finding the volume of the solid generated by revolving the area
@mark44, sorry.. thanks guys, so is the answer ∏/6 cubic units?- stardust006
- Post #6
- Forum: Calculus and Beyond Homework Help
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High School Resistors that doesn't affect the others
Yes, thanks a lot! :)- stardust006
- Post #3
- Forum: Electromagnetism
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High School Resistors that doesn't affect the others
hello! we got this experiment, R1= 46.8 R2= 46.8 R3= 148.9 R4= 147.7 R5= 217 RT= 71.1 as we can see, r1 and r2 are in series, while r3 and r4 are in series also and they are parallel to each other while r5 is on the middle, we got the RT by solving for r1,r2,r3 and r4. and here's...- stardust006
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- Resistors
- Replies: 2
- Forum: Electromagnetism
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Finding the volume of the solid generated by revolving the area
find the volume of the solid generated by revolving the area bounded by the given curve about the indicated axis:y = 2x-x^2 and y = x; about the y-axis The attempt at a solution: so i assigned values for x and y, and the curve is a parabola that opens downward with a vertex of (1,1), i used...- stardust006
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- Area Solid Volume
- Replies: 7
- Forum: Calculus and Beyond Homework Help
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Finding the area of the loop of the curve y^2=x^3(1-x)^2
Thank you, I should practice my math T.T- stardust006
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding the area of the loop of the curve y^2=x^3(1-x)^2
Find the area of the loop of the curve y^2=x^3(1-x)^2 using integral calculus. y=√x^3(1-x)^2 y=√x^3/2 (1-x) To sketch the curve, I assigned values for x and then solved the corresponding values of y. x= -1, y= -2 x= -0.5, y= -0.53 x=0, y= 0 x= 0.5, y= 0.177 x=1, y=0 how can i...- stardust006
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- Area Curve Loop
- Replies: 2
- Forum: Calculus and Beyond Homework Help