I thought so, since the problem says that theta goes between pi/2 and pi i.e. large angle scattering is from 90-180 degrees. I don't see how I'm supposed to get it to be 4pi instead of 8/3.
Homework Statement
Integrate the rutherford cross section over the backward hemisphere to get 4pi(sigma0(E))
Homework Equations
Rutherford cross section is sigma0(E)/sin^4(theta/2)
The Attempt at a Solution
When I integrate this with the limits pi/2 to pi i get sigma0(E)*(8/3) i...
ok, so I've worked it up to the point where I have the new abundancy = .0065e^(lambda238-lambda235)*4.5billion years but it's wrong. How can i fix this?
Well, N/N0 would be the probability that a nucleus has decayed in the given period of time which in this case would be -4.5billion years if we take t=0 to be the present. And can't N be larger than N0 if we are going back in time?
Homework Statement
The Earth is about 4.5 billion years old. If 235U is 0.65% abundant today, how abundant was it when the Earth formed? Note, in this case abundancy is defined as the ratio of Uranium 235 to Uranium 238Homework Equations
R=N(lambda)
N=N0e^-lambda(t)
Half Life = ln(2)/lambda...