Recent content by Swan

no information about the receiver is given and also no speed is given throughout this question

Homework Statement You are the quarterback for the Quinte Saints Football team. You are in the middle of the COSSA gold medal game and you see your receiver is wide open down the field beside the sideline. If he catches the ball, you win the game. However, the biggest guy Joey from the...

Homework Statement The following enclosure is built using 280 m of fencing. If the enclosure has a total area of 2800 m2, what are the dimensions to the nearest tenth? Homework Equations x = \frac{-b ± \sqrt{b^{2}-4ac}}{2a} The Attempt at a Solution Please note that the 3/2w and 5/2w...

Homework Statement You are the quarterback for the Quinte Saints Football team. You are in the middle of the COSSA gold medal game and you see your receiver is wide open down the field beside the sideline. If he catches the ball, you win the game. However, the biggest guy Joey from the...

I got at m = 3 and m = 4 the diffraction grating would produce a maximum at 11° at visible wavelengths of 636 nm, 477 nm respectively to m = 3, m = 4.

Hello tiny-tim. Thank You for replying. How would i go about solving this question?

Homework Statement A monochromatic plane wave is normally incident on a diffraction grating with 105 lines/m. For what visible wavelengths would this grating produce a maximum at 11°. Homework Equations d*sinθ = m*λ The Attempt at a Solution d = 1 x 10-5 m I don't get how to...

Ok, Thank you tiny-tim. :)

Homework Statement The diagram shows three charges, A (+5.0 μC),B (-7.0 μC), and C (+2.0 μC), placed at three corners of a rectangle. Point D is the fourth corner. What is the electric potential at point D? Homework Equations VEL = \frac{(k)(q1)}{d}The Attempt at a Solution I don't know how...

I would let the system have 0 kinetic energy at the top to reach its max height.

Ok, thank you.

The original question with different values was going down the incline in which all worked out. But then when teacher modified when making it go up the incline, I'm getting an error.

Its from the Nelson Physics 12 but I think the question was modified by the teacher.

I tried it. It still yields a negative which will result in a error through square root. Is there any error in the derivation of my equation?

Firstly, thank you so much for replying quickly :). In the question it says "(above the completely extended spring)" meaning the the box has to move 1.3m after full extension. At the moment the box is on the spring, it is compressed 0.4m and therefore total distance becomes (1.3m + 0.4m =...