Recent content by sylenteck0

Right right. Thanks so much :)

Constant velocity means no acceleration And ah, ok :)

Alrighty. But even if I do include the kinetic friction, how would I find a?

Homework Statement Two blocks are connected over a pulley. The mass of block A is 10 kg and the coefficient of kinetic friction between A and the incline 0.20. Angle theta of the incline is 30 degrees. Block A slides down the incline at constant speed. What is the mass of block B...

According to the answer sheet, the answers I got are correct, but I'll get on thinking about that :)

Ah, so what I found was the force of the bicycle on the road? So, the net force on the bicycle on the road would be the reactive force from gravity, making it 9.8 x 85.0 kg, right? (Which is 833N)

Homework Statement A bicyclist travels in a circle of radius 25.0m at a constant speed of 9.00 m/s. The bicycle-rider mass is 85.0 kg. Calculate the magnitudes of a) the force of friction on the bicycle from the road and b) the net force on the bicycle from the road. Homework Equations...

So I could theoretically use the velocities in place of the coordinates themselves? m= 0i+ 16.66m/s t j p=22.22m/s t i+ 0 j Something like that? I can see finding the derivative that way =P

I've tried subtracting the one vector from another, but I can't find a way to get the derivative; it always ends up as zero because there's no variable. What would serve as the variable in this case?

Yup. Thanks for the advice :)

Homework Statement Two highways intersect. A police car P is 800 m west from the intersection and moving at 80km/h west. Motorist M is 600m north of the intersection and moving at 60 km/h south. a) in the unit-vector notation, what is the velocity of the motorist with respect to the police...

Thanks for the warm welcome, and I'll be sure to look it over :)

Homework Statement A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 3.00 m higher than A, with speed 1/2 v. Calculate (a) the speed v and (b) the maximum height reached by the stone above point B. Homework Equations Time in the sky= Initial...