Recent content by TalliThePrune

Wonderful! I won't say I didn't consider it for a minute... But that would imply one field disappears with the presence of another, so no! So VPlanet + Vmoon: - 5.93 x 104 + - 8.89 x 107 = - 1.429 x 108 Thanks so much for your help. :smile:

Whoops! Sorry moon. Does this mean I calculate V for both the planet and the moon, and add the two? So for the moon... V = - (6.67 x 1011) x (4.8 x 1022) / (5.4 x 107) V = - 5.93 x 104

Homework Statement :[/B] "Calculate gravitational potential at point Z, which is 8.10 x 107m away from a planet of mass 1.08 x 1023. " (This point is between the planet and a moon, where the gravitational field strength is zero. I'm not sure if that makes a difference. The moon's mass is 4.8 x...

Yeah, I've just been doing questions on that actually! :smile: Clearly my sketch isn't the best, I meant it to look similar to this electric field diagram except with arrows pointing at both masses (instead of one way towards the negative/away from the positive). I just can't seem to find any...

Homework Statement "Complete the diagram to display gravitational field lines between two objects of equal mass." Homework Equations N/A as question is descriptive.The Attempt at a Solution Okay, I know it's a bit of a mess but what I'm trying to show here is that the fields are radial and...

I couldn't tell you. But unfortunately this is the entire question, I haven't omitted anything.

Homework Statement "An object is moving in a straight line from a positively charged area (A) to a negatively charged area (B). Explain how the electrical force and electrostatic potential energy experienced by the object will vary when it is neutral (has no charge)." Homework Equations N/A as...

Ah! Thanks so much for clarifying, I was too stressed to spot what he'd done. :-p

@andrevdh , did you use the same formula / figures as I did in the OP? I'm very worried about doing this wrong as I have an exam tomorrow.

Thank you! :biggrin:

1. Calculate the gravitational field strength at 500km above Mars' surface. Mass of Mars: 6.39 x 1023 kg Radius of Mars: 3.39 x 103 km Constant G: 6.67 x 10-11 2. I used the equation g = GM / r23. To begin with I added the 500km height above ground to the radius, giving 3.89 x 103 km. I then...