Homework Statement
Hi
i've noticed that,
J^{ab}P^c + J^{bc}P^a+J^{ca}P^b = 0
[
Since
J^{ab}P^c + J^{bc}P^a+J^{ca}P^b = x^a\partial^b\partial^c -x^b\partial^a\partial^c + x^b\partial^c\partial^a-x^c\partial^b\partial^a+x^c\partial^a\partial^b-x^a\partial^c\partial^b = 0
]
Next, I tried it on...