A simple equality of Generalized Lorentz Operators

[tamiry]

Homework Statement

Hi

we have Lorentz operators
J^{\mu\nu} = i(x^{\mu}\partial^{\nu} - x^{\nu}\partial^{\mu})

and these have
[J^{\mu\nu}, J^{\rho\sigma}] = i(\eta^{\nu\rho}J^{\mu\sigma} + \eta^{\mu\sigma}J^{\nu\rho} - \eta^{\mu\rho}J^{\nu\sigma} - \eta^{\nu\sigma}J^{\mu\rho})

Now define generalized rotation operators, for i, j, k space coordinates
M^{i} = \epsilon_{ijk}J^{jk}

Show that M^{i} have the SU(2) algebra. i.e.
[M^{i}, M^{j}] = i\epsilon_{ijk}M^{k}

Homework Equations

(all is above)

The Attempt at a Solution

I've done a few attempts and failed. so I tried taking an example
M^{1}= \epsilon_{123}J^{23}+\epsilon_{132}J^{32} = J^{23} - J^{32}
M^{2}= \dots = J^{31} - J^{13}

and now
[M^{1},M^{2}] = [J^{23}, J^{31}] - [J^{32}, J^{31}] + [J^{23}, J^{13}] - [J^{32}, J^{13}]

well J^{ij} = -J^{ji} so the second term negates the first one (J^{32} for J^{23}) and like wise the fourth and third term. So all in all I get zero. and that's no SU(2) :(

where did I go wrong?

thanks a lot for reading this
Tamir

 

[TSny]

Hello, tamiry.

Now define generalized rotation operators, for i, j, k space coordinates
M^{i} = \epsilon_{ijk}J^{jk}

Did you leave out a factor of 1/2 here?

[M^{1},M^{2}] = [J^{23}, J^{31}] - [J^{32}, J^{31}] + [J^{23}, J^{13}] - [J^{32}, J^{13}]

J^{ij} = -J^{ji} so the second term negates the first one (J^{32} for J^{23}) and like wise the fourth and third term. So all in all I get zero.

Those terms don't cancel. Watch the signs carefully.

 

[tamiry]

but of course...
thanks!