Recent content by tariel

Probably me! I was holding it above while simultaneously trying to make the ball bounce directly below. I'll just take note of the discrepancy in the write up, since it's basically saying the ball gained energy somehow, haha.

I knew it was simpler than what I was doing! Okay, so since I have max. heights for each of the bounces, I can find PE as g*h. So before impact, KE = PE. After impact, KE would be the PE of the following bounce, correct? And since momentum is the velocity in this case (no mass was recorded)...

Sorry, I'll go back to the beginning. I have a feeling this is simpler than what it seems, but my tutor has yet to respond to me. Yes, the sensor was held vertically above the bouncing ball. The data collected produced this graph: http://i.imgur.com/QSxyot1.png y-axis is the vertical distance...

Well... that was a lot easier than expected. Thanks for your time!

I used a motion sensor hooked up to Logger Lite software, can't remember the exact specifics as I did the data collection some time ago. I just want to make sure I'm doing this right, my tutor hasn't responded to me yet. So for the second bounce, using your equation, this is what I did: Bounce...

y = 2/3 x ? So 2/3 is the slope? And since there's no b, this means that y = 0?

Homework Statement Rolling Motion Theoretically, a=⅔g sin θ suggests a nonlinear relation between a and θ. Since a linear graph is a very convenient method of testing theoretical equations, it is a good idea to first linearize a=⅔g sin θ. A simple way to do this is to assign a as the...

So the B value would stay the same?

Hi guys. I've been a lurker for a while, but I've recently become super stumped on this physics question (physics is far from my forté). I've attached the graph of my bouncing ball. First, I had to identify the coefficients and what they mean. I understand that A is acceleration, B is initial...