Recent content by tbaskerv

NO! Keep going! I need help on this problem. I'm stumped. Ok so let's start over, For my example everything is the same but the guy is 78 kg mu of the feet is 0.84 and mu for the back is 0.64. I found mg = 764 So I need to make the vertical force resisting equal 764. The vertical force is...

I'm solving the same problem. I don't understand how to find the friction force. Can someone explain in this particular problem?

Nevermind, it was as simple as multiplying the coefficient by gravity, sorry for the space waster.

Homework Statement What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.30? Homework Equations sigmaFy = Fn-mg = may = 0 sigmaFx = Fp - Ffr = max = 0 Ffr = (mew)s * Fn Fp = Ffr = (mew)*Fn Fp = (mew)s(mg)...

Nevermind, another problem helped me out, thank you! More will come!

THANK YOU! THIS HELPED ME A LOT! Ps: you were right. You need to take your accelerated force, add the anti-retarded force, and then divide by cos(theta). I've spent a good 24 hours stuck on this, god bless you both.

Homework Statement A person pushes a 13.0 kg lawn mower at constant speed with a force of 77.0 N directed along the handle, which is at an angle of θ = 49.0° to the horizontal. Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.8 m/s in 2.0 seconds...