How Is Maximum Car Acceleration Calculated with a Friction Coefficient of 0.30?

AI Thread Summary
The maximum acceleration of a car with a coefficient of static friction of 0.30 can be calculated using the formula Fp = (mew)s * mg, where Fp is the force due to friction, mew is the coefficient of static friction, m is the mass of the car, and g is the acceleration due to gravity. The user initially struggled with the problem, expressing confusion over the need for the car's mass or initial velocity. However, they later realized that the solution is straightforward and involves simply multiplying the friction coefficient by the acceleration due to gravity. This results in the maximum acceleration being 0.30 times the gravitational acceleration. The discussion highlights the importance of understanding the relationship between friction and acceleration in vehicle dynamics.
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Homework Statement




What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.30?

Homework Equations


sigmaFy = Fn-mg = may = 0
sigmaFx = Fp - Ffr = max = 0
Ffr = (mew)s * Fn
Fp = Ffr = (mew)*Fn
Fp = (mew)s(mg)

mg is mass times gravity
* are multiplication
(mew)s = static friction
Fn = normal force


The Attempt at a Solution



Um...I have no clue how to solve it, any direction to point me in would be helpful. I can't see how to solve it without the mass of the car, or the initial velocity.
 
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Nevermind, it was as simple as multiplying the coefficient by gravity, sorry for the space waster.
 
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