Recent content by terryfields

just need 2 definitions without proof for an exam tomorrow, don't need to use them for anything just need to be able to quote them but can't find them anyway so if someone could helpfully write them down that would be great 1)simple graph 2)connected graph cheers

stuck on a question on register machines for revision, basically i don't have the notes for these problems but i do have the questions and answers. the question starts off giving us the information 1(1,2,7) 2(2,3) 3(1,4,9) 4(2,5) 5(1,6,10) 6(2,1) 7(1,8) 8(1,9) 9(1,10) 10(halt)...

similarly x-pi<y<x (u+v)/2-pi<v-u<(u+v)/2 -2pi<-2u<0 -u<v<pi-u

rite I've got limits of 0<x<pi/2 and x-pi<y<x with u=x-y, v=x+y with a transformation from f(x,y) to f(u,v) which isn't really needed for what I am about to ask i get he jacobian as 1/2 then get y=(v-u)/2 and x=(u+v)/2 all of which i know is right as i have the answers, this is purely...

thanks, that's much simpler than it first looked.

Ok, so the basis formed by the polynomial is always going to be one higher than the degree of the polynomial, therefore value of n that will make Pk isomorphic to n has to be k+1? (crosses fingers and preys)

so for a second degree polynomial you would have ax2 +bx +c so is the answer just n-1 because the dimension of a polynomial is always one higher than the degree?

posted on wrong post sorry

problem here on a kernal and range question. on the first part of the question it asks me to define what is meant by kernal and image of a mapping T:U>V answers being kerT={uEU:T(u)=0} and imT=T(U)={T(u):uEU} then there's a second part to the question asking me to state the definitions of rank...

sadly not been able to put much effort into this one! was a lecture i missed towards the end of term and didnt get the notes on it, however here is the question. for K>or equal to 1 let Pk denote the the vector space of all real polynomials of degree at most k. For which value of n is Pk...

thanks guys, off out now but will read through that later, from first glance i think all my problems are answered =)

f=z2 +zsin(xy)?? is there a method to do this by or is it just inspection to find it?

i think i understand so when we get zsin(xy)i +zsin(xy)j+z2 from integrating we have to check what we would get from differentiating this? in this case the i term and j term don't need constants because they would differentiate right back to what they were integrated from? however for the...

ok, so by my calculations i would get (zsin(xy))i+(zsin(xy))j+(zsin(xy)+z2)k i assume this is how it's writen? as i now assume i need to do ∇ x f = 0 to find my constants?

ah ok, so do i just need to integrate each term in respect to x or in respect to x,y and z?