Recent content by thaixicedxtea

nvm... got it...

Homework Statement Given: The coefficient of static friction between the person and the wall is 0.66, the mass of the person is 73 kg, the radius of the cylinder is 7 m, and g = 9.8 m/s. A barrel of fun consists of a large vertical cylinder that spins about the vertical axis. When it spins...

Homework Statement As shown in the figure, a block is pushed up against the wall. Let the mass of the block be m=2.3 kg, the coefficient of kinetic friction between the block and the wall be µ= 0.53, and θ= 62. Suppose F = 68 N. The acceleration of gravity is 9.8 m/s^2. Find the force of...

Yes so I got Vo as 33 m/s and I did get theta as 58! Thank you so MUCH!

so I solved for time and got 2.85 seconds using Vx = x/t I get Vx to be 17.5 m/s.

Vy is zero and I assumed Yo to be 0 too. I got Vyo to be 28 m/s. The only equation I know that relates all my info given is y= Yo + VyoT + 1/2 at^2 to get time. Am I supposed to use that? I don't know about horizontal velocity though. Trig?

Ummm Req maximum height to hit the first target is 40 m. I know that at target 1 that Vy is 0, right? The required range so that the arrow hits target 2 is 100 m. Vy^2 = Vyo^2 + 2a(y-yo) ?

Homework Statement Target #1 and Target #2 are placed as shown. The one on top is made of paper so that an object hitting it will pass right through without its motion being disturbed. At what velocity and angle must you shoot an arrow so that it will pass through target #1 and land on target...

C equals pi * diameter, so the circumference of the ring is 2.26 cm * pi = 7.09. Is that the length? If it is, why? I must be thinking too hard...

Homework Statement You somehow manage to get a gold ring with inner diameter 2.26 cm stuck on your finger, even though your knuckle has a diameter of 2.3 cm. The temperature of the ring is 23 degrees C. To what temperature would you have to heat the ring in order to get it off your finger...

Oh, now I understand... so the height would be the length times two since the length is considered the radius of the circle, right? Height would be the length times two for the full round top to bottom. Plus the height from the ground to the lowest point of the circle, P, because the floor is...

Homework Statement A .10 kg solid rubber ball is attached to the end of a .80 m length of light thread. The ball is swung in a vertical circle. Point P, the lowest point of the circle, is .20 m above the floor. The speed of the ball at the top of the circle is 6.0 m/s, and the total energy of...