Hi GreenPrint.
What are your initial thoughts? Also, I assume a is an arbituary constant and not specified as anything else in your original question.
The Bob
I agree with eumyang. Is the question to simply the above expressions? Also, with the second problem, are you missing any brackets/parenthesis at all?
The Bob
Hi hossai. Welcome to PF!
The idea of these threads is to help each other solve problems they have. So, if you'd like to venutre an attempt at the solution or method for solving this then we could discuss it further.
The Bob
Ok, try here (http://en.wikipedia.org/wiki/Lists_of_integrals#Definite_integrals_lacking_closed-form_antiderivatives) under the section 'Definite integrals lacking closed-form antiderivatives' and see if that helps.
If not look at this (http://www.soton.ac.uk/~adf/pubstore/pub20.pdf ).
The Bob
Hi Atlaπtis. Welcome to PF!
I once did any experiment with an air track and I had to see if different shaped sails made a difference to a 'boats' propulsion. I attached weights to one end and found the distance the 'boat' would travel and plotted it again mass for each. I had some problems...
Because you know the force needed to overcome friction down the slope and also the normal reaction so could work out the coefficient of friction. However, you don't really need this to work it out. As you know the other information in your question you can find the work done by comparing initial...
I'll just list some books as history seems to be prevailing:
> 'Animal Farm' - George Orwell
> 'Nineteen Eighty-Four' - George Orwell
> 'The Hitchhiker's Guide to the Galaxy' Trilogy - Douglas Adams
> 'To Kill a Mockingbird' - Harper Lee
> 'The Marriage of Heaven and Hell' - William Blake...
Hi mimib1230. Welcome to PF.
Try starting by spliting the weight of the mass into components. From this you'll have a force down the slope (but which one?) and this will then allow you to substitute the value into an equation (but which one?). See what you make of that. I will not give you...
Just for my own clarity, does it make a 60° angle with the bit that goes in the ground or with the actual shade itself? Could you produce a diagram if this seems to be a silly question?
The Bob
That's not the right first, step. What do you know about the addition of logs? If that doesn't help, substitute a = 5 and b = x2 and re-ask my question.
The Bob
Hey bmiceli21,
Glad you've got a solution and thanks for posting it. Apologies for the misunderstandings on my part and well done to your colleague.
The Bob