Rewriting expression of logarithm

AI Thread Summary
The expression log55x2 can be rewritten using logarithmic properties. Initially, it was attempted to express it as 2log55x, but this was incorrect. The correct approach involves separating the logarithm into a sum: log55 + log5x2. This simplifies further to 1 + 2log5x, providing the final rewritten expression. The discussion emphasizes the importance of understanding logarithmic addition and substitution for accurate transformations.
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Homework Statement


Rewrite the expression as a sum, difference or multiple of logs.

log55x2

Homework Equations





The Attempt at a Solution



log55x2 =
2log55x =
...
 
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That's not the right first, step. What do you know about the addition of logs? If that doesn't help, substitute a = 5 and b = x2 and re-ask my question.

The Bob
 
ooh~
log55 + log5x2 =
1+log5x2 =
1 + 2log5x2!
thank you so much
 
Make that 1 + 2log5x and you're there.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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