now I've used this velocity to find L'
L'=1ly(1-(.873c)^2/(3e^8)^2)^1/2
simplifying i got L'= 5.17681e15m= .547ly as measured by the pilot
now for the time dilation
T=1year(1+(.871c)^2/(3e8)^2= 1.759 years as measured by an earthclock
okay, i used lorentz transformation:
Δx=γ(Δx'+vt) and Δt=γ(Δt'+(vΔx/c^2))
had unknowns of v and Δt so for the first equation i solved for v and got
1ly/√(Δt^2+9.94456e14)
substituted that into the other lorentz equation and got
Δt=√1/(1-(ly/√Δt^2+9.94e14)^2/3e8) *...
used equation gamma(mu)=p . For particle #3 got a velocit of m<-4/3c,-3/4c>. arctan (3/4 / 4/3 )=29.36
now I am trying to use u_y'= u_y/(gamma(1-(u_xv/c^2))) to find the relative y velocity between them but ended up with 1.017c
If a spaceship travels a distance of one light year as measured from Earth in one year's time as measured from the spaceship what is the relative velocity for earth-ship. Also how far did the pilot travel according to the pilot and how long was the trip according to an earth-clock?
I found...
If a particle of mass M is at rest in a lab when it decays into 3 identical particles of mass m with:
particle 1: having a velocity of 4c/5 in the -i direction vector
particle 2: having a velocity of 3c/5 in the -j direction vector
particle 3: having an unknown velocity in a direction defined...