Recent content by thisisfudd

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    What is the voltage across each capacitor in this circuit?

    So that means that the total capacitance is 7?
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    Currents and resistors and series and parallel you get the idea

    So using these formulas I get the right answer for the first resistor. But when I plug back into get I2, I instead get the current for resistor number 3. Any ideas?
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    Currents and resistors and series and parallel you get the idea

    So is the current "in the resistor" the same as the current going around the loop?
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    Currents and resistors and series and parallel you get the idea

    Hi, ok so if I2 in the top and bottom equations are different, how can I solve for, for instance, I2? Sorry, I should have mentioned that the positive terminals point outward on each battery. So given that, I'm really not sure how I keep messing this up.
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    What is the voltage across each capacitor in this circuit?

    If 26 V is applied across the following network, calculate the voltage across each capacitor: Ignore the dots, it's just spaces between the two ends ___ 3.00 uF _____ 4.00 uF |.......| |.......| __________2.00 uF______ |.......| |.......| |.......| So I know that for capacitors in...
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    Currents and resistors and series and parallel you get the idea

    OK, I think I get what you're saying. So I did this: 9V + 25I1 + 18I2 = 0 21V + 25I1 + 35I3 = 0 12V + 35I3 - 18I2 = 0 I1 = (-9 - 18I2) / 25 = -.36 - .72I2 I3 = (-12 + 18I1) / 35 = -.34 + .51I2 21 + 25 -.36 - .72I2) + 35 (-.34 + .51I2) = 0 I2 = .67 Does this look better? I...
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    Currents and resistors and series and parallel you get the idea

    Ugh, I am totally stressed out by this. Here is what I've done: 9V + 25I1 + 18I2 = 0 12V + 9V +25I1 + 35I3 = 0 12V + 35I3 + 18I2 = 0 I2 = (-9 - 25I1) / 18 = -.5 - 1.39I1 I3 = (-21 - 25I1) / 35 = -.6 - .71I1 12 + 35 (-.6 - .71I1) + 18 (-.5 - 1.39I1) = 0 -21 - 25.56I1 - 9 - 25.02I1 =...
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    Currents and resistors and series and parallel you get the idea

    Yeah, I get that. But could you tell me if I am going in the right direction? Because I tried doing that and my answers are far larger than those I expect.
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    Resistors in series and parallel

    OK, so the current provided by the battery will change: it will decrease. I think the current in the 6 ohm resistor might increase because it is no longer connected in parallel to anything else. Is this correct?
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    Currents and resistors and series and parallel you get the idea

    OK I still do not understand AT ALL. I don't understand how I am supposed to add volts and ohms together. I tried setting up two equations whose sums equal zero and then substituting, but it didn't work? 9 V + (I1 x 25 ohms) + (I1 + 18 ohms) = 0 9 V + 12 V + (I1 x 25 ohms) + (I2 + 35 ohms)...
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    Resistors in series and parallel

    A 3 ohm resistor is connected in parallel with a 6 ohm resistor. This pair is then connected in series with a 4 ohm resistor. These resistors are connected to a battery. What will happen if the 3 ohm resistor breaks? I think that the power dissipated in the circuit will increase. The...
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    Extension cord connected to heater - Find the power

    Huh. Awesome. Thanks for your help!
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    Extension cord connected to heater - Find the power

    OK, so I have found resistance, .00867. So then I can use P = RI^2? P = .00867 x (15.0A)^2? Your PS is intriguing but of course I don't understand. Are you saying that it draws 15 A on a 120 V line but I have to find what it draws on this line, given the voltage of this line? How would...
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    Extension cord connected to heater - Find the power

    An extension cord made of two wires of diameter 0.129 cm (no. 16 copper wire) and of length 2.7 m is connected to an electric heater which draws 15.0 A on a 120V line. How much power is dissipated in the cord? Do I just use P=IV? But that leaves a lot of "extraneous" information. My...
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    Currents and resistors and series and parallel you get the idea

    So this problem asks you to determine the magnitudes and irections of the currents in the resistors. I definitely understand how to determine directions, using Kirchhoff's Rules. But here is where I get stuck: the batteries have emfs of E1 = 9.0 V and E2 = 12.0 V and the resistors have vlaues...
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