Resistors in series and parallel

AI Thread Summary
When a 3 ohm resistor in parallel with a 6 ohm resistor breaks, the overall resistance of the circuit changes. The current through the 4 ohm resistor will not drop to zero, as it remains connected to the battery. Instead, the current in the 6 ohm resistor is likely to increase because it is no longer in parallel with the 3 ohm resistor. The total current provided by the battery will decrease due to the change in circuit configuration. This analysis highlights the importance of understanding how resistors interact in series and parallel configurations.
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A 3 ohm resistor is connected in parallel with a 6 ohm resistor. This pair is then connected in series with a 4 ohm resistor. These resistors are connected to a battery. What will happen if the 3 ohm resistor breaks?

I think that the power dissipated in the circuit will increase.

The other choices are that the current in the 4 ohm resistor will drop to 0, that the current in the 6 ohm resistor will increase and that the current provided by the battery will not change.

I think I am right because the 4 ohm is connected to two parallels, it will therefore not change. Is this reasonable?
 
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both answers are wrong... and not reasonable...
draw the graph first, and "see" what's going on...
imagine current is an incompressible fliud in water pipe
 
OK, so the current provided by the battery will change: it will decrease. I think the current in the 6 ohm resistor might increase because it is no longer connected in parallel to anything else. Is this correct?
 
I am thinking the same thing too
Becuase current does not split into two ways any longer after it left the 4 ohms resistor, so the current would increase
 
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