Recent content by tmclary

Thanks for your help, Def & Hoot!

So 1/(4x^2)+4x+5 =1/((2x+1)^2)+4 and I make a u-sub. Looks like tan^-1 type integral. Correct?

Sorry, I have no clue how to get started. The denominator won't factor (at least to linear factors w/ integral coefficients) and the discriminant is complex anyway. So if it's a partial fraction type solution, how do you get started? Thanks.

Homework Statement Integrate the indefinite integral of 1/((4x^2)+(4x)+5) Homework Equations The Attempt at a Solution

D'oh Yup, yup and yup. Sheesh, the careless algebra mistakes I can make are embarrassing. thanks H.O.V.

Sorry, I meant B and C?

Your answer to part a) ... ... isn't quite right. Hint: What is the y-int of lines connecting A and C ? A and B?

Remember to use two integrals... Your first integral evaluates 4e^x from 0 to 3, then subtract the integral of x (dx) from 0 to 3 (since it's the area between the curves, and 4e^x is always greater than y=x.) Your answer should then be (4e^3-4e^0) - ((3^2)/2 -(0^2)/2) = 4e^3-4-(9/2) = 4e^3...

Use Hall of Ivy substitution in the above equation: (6^2x)y=(6^y)4.

Got it- I wasn't adding the 1 to the 4/n. Thanks again for your answer.

Thanks very much for your replies- I'm still stuck expanding the summation- will attempt another query when I have time, and can clarify.

Sorry-wrong limits! Sorry! The limits were 1 to 5, not 2 to 5!

[SOLVED] Upper Bounds Integration Homework Statement Integrate y=4x from 2 to 5 using the limit with circumscribed rectangles. Homework Equations A=lim(n to inf.) Summation of f(xsubi) times delta (xsubi) The Attempt at a Solution A=lim(4/n)(4/n)(4)(2+3+4+...+(n+1))...