Recent content by TogoPogo
-
T
Determining the convergence/divergence of this series
Thanks for your help. If I'm not mistaken, isn't ## \frac{1}{n^{\ln 2}} ## divergent? Or is there another series that I should be comparing to?- TogoPogo
- Post #7
- Forum: Calculus and Beyond Homework Help
-
T
Determining the convergence/divergence of this series
That's correct- TogoPogo
- Post #5
- Forum: Calculus and Beyond Homework Help
-
T
Determining the convergence/divergence of this series
Apologies, it should be as x approaches infinity... Thanks for the fix!- TogoPogo
- Post #3
- Forum: Calculus and Beyond Homework Help
-
T
Determining the convergence/divergence of this series
I am required to determine the convergence/divergence of the following series: $$ \sum_{n = 2}^{\infty} \frac{1}{(ln(n))^{ln(n)}}$$ Which test should I use? Wolfram Alpha says that the comparison test was used to determine that it was convergent, but I have no idea what series I should compare...- TogoPogo
- Thread
- Series
- Replies: 9
- Forum: Calculus and Beyond Homework Help
-
T
Solve DE Using Substitution and Integration Techniques | Helpful Tips Included
I got it! Thank you. I didn't know how to integrate secx but Wolfram helped out.- TogoPogo
- Post #3
- Forum: Calculus and Beyond Homework Help
-
T
Solve DE Using Substitution and Integration Techniques | Helpful Tips Included
The problem states: "By using the substitution y=xu, show that the differential equation \frac{dy}{dx}=\frac{y+\sqrt{x^{2}+y^{2}}}{x}, x>0 can be reduced to the d.e. x\frac{du}{dx}=\sqrt{u^{2}+1}. Hence, show that if the curve passes through the point (1,0), the particular solution is given by...- TogoPogo
- Thread
- Replies: 2
- Forum: Calculus and Beyond Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
Nevermind, it seems that the solution was online. Looks like factorization actually has something to do with the product of the line segments. http://www.cut-the-knot.org/arithmetic/algebra/ProductOfDiagonals.shtml#Solution However, I don't understand the part where it says "This is a...- TogoPogo
- Post #12
- Forum: Precalculus Mathematics Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
Thanks, that made a lot of sense (surprisingly!). I'm going to go work on this for a while now and report back if I make some progress (unlikely lol) By the way, this is for a grade 11 IB math class. I think I'm overthinking the assignment a bit too much. I was thinking if I could just use...- TogoPogo
- Post #11
- Forum: Precalculus Mathematics Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
Thanks! I guess the real problem that confuses me is how the factorization of z^n - 1 = 0 can be used to prove the theorem that the product of the distances is equal to n... EDIT: Is there any way to express the distance of, for example, |z0-z2| in terms of |z0-z1|? Or just expressing the...- TogoPogo
- Post #9
- Forum: Precalculus Mathematics Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
There's a proof for de Moivre's on the Internet that shows you how raising cisx to the nth power is the same as cisnx- TogoPogo
- Post #6
- Forum: Precalculus Mathematics Homework Help
-
T
How Can Trig Double Angle Formulas Simplify This Function?
Homework Statement Hello, I am trying to simplify the inputted function here http://www.wolframalpha.com/input/?i=sqrt%282%29+sqrt%281-cos%28%282pi%28x-y%29%29%2Fn%29%29 which is \sqrt{2}\sqrt{1-cos[2\pi(x-y)/n]} to the form of 2sin[(x-y)\pi/n] Homework Equations Not sure The Attempt at a...- TogoPogo
- Thread
- Function Trig
- Replies: 7
- Forum: Precalculus Mathematics Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
I don't quite understand the conjugate pair part. Could you give me an example for factoring z^{3}-1=0? I found the roots via de Moivre's to be 1, -\frac{1}{2}+\frac{\sqrt{3}}{2}i, and -\frac{1}{2}-\frac{\sqrt{3}}{2}i. Then would the factored form be...- TogoPogo
- Post #4
- Forum: Precalculus Mathematics Homework Help
-
T
Factoring the equation z^(n)-1=0 where z is a complex number
Homework Statement Hey, I am attempting to fully factorize z^{n}-1=0 for all integers of n where n does not equal zero, and where z is a complex number in the form a+bi. The question asks to first factorize the equation when n=3,4,5. I know how to factorize when n=3 and 4, but I get stuck at...- TogoPogo
- Thread
- Complex Complex number Factoring
- Replies: 13
- Forum: Precalculus Mathematics Homework Help