Recent content by Tonia

For i) i meant to say 2 electrons

< Mentor Note -- thread moved to HH from the technical chemistry forum, so no HH Template is shown >[/color] I need someone to check my answers and help me with the questions I couldn't answer. What is the max. # of electrons located in the groud state of a) an orbital 2 b) d sublevel 10 c)...

Is there a reason you used four zeros?

The atom that is used as the standard for the atomic mass scale is the Carbon atom with an atomic number of 6 and a mass number of 12 and this carbon atom is equal to 12 unified atomic mass units. Could another atom be used as the standard, and if so, how would this be accomplished??

Thankyou

Where is the fifth energy level in relation to the fourth energy level? Well, it shows that energy level five is at n= 5 and energy level four is at n=4 away from the nucleus, so that means that the fifth energy level is at the 16th orbital and energy level four is at the 25th orbital?? I am not...

I came across Farsel Juice while looking up examples of how to write lab reports. What is Farsel Juice??

55.8 ft/sec - 45 ft/sec = 10.8 ft/sec 10.8ft/sec/6.30ft/sec^2 = 1.714 sec. = 1.7 seconds d) determine how much of the 300 ft displacement is due to the initial velocity and how much is due to the acceleration e) find the time required for traveling the first 150 ft.

Okay, thanks!

Let me ask you one more question just to make sure: for problems a) and c), the answer is the same? 22.5mi/hr??

Okay. thanks for your help!

so t is 2.5 seconds and that's the answer to d.

22.5 mi/hr

t would be 5.

45 mi/hr = 0 + 9 mi/hr/sec times t Solve for t??