Recent content by Tubs

I am trying to write a fortran program to take an integer n and print out the first n rows of Pascal's triangle. The code I have so far: PROGRAM PascalTriangle IMPLICIT NONE INTEGER i, n, j, ktemp, ktemp1, ktemp2, ktemp3, ktemp4, ktemp5 WRITE(6,*), "Enter a positive integer n:> "...

Ok, thanks a lot. Another quick one that I am stumped on: A thin rod rotates around one end. Its angular acceleration is 3/2 radians / second^2 and has a rotational kinetic energy of 1.60 J at t = 4s. What is the kinetic energy at t = 0s? A graph was given of this question, pretty much...

I can't seem to get past this one, and it should be possible to solve without using integration. Any help would be great :D A 0.25 kg object is stationary on a frictionless surface. At t = 0, a horizontal force begins to move the object. The force is given by F = (12 - 3t^2) and acts until...

This question is making me go in circles, any tips? A car weighing 200000 N traveling 3 m/s slams into a stationary car weighing 400000 N. The collision connects the two cars. How much energy is transferred from kinetic energy to other forms of energy in the collision?

Looks like it. Your other one was even easier :wink:

I'm guessing you mean how do you find the z coordinate. Since a box has uniform length in every dimension it is easy to find the COM in every component through symmetry.

The comment on that question was that it was difficult. Compared to these other ones it is simple, I should have seen that answer right away. STUPID STUPID STUPID STUPID :mad:

Fnet1 = ma 12 = (4)a a = 3 m/s^2 Fmax = ma = 9(3) = 27N All good?

If a 4kg block is resting on a 5kg block and the maximum horizontal force exerted on the block without it moving is 12N, what is the maximum horizontal force that the bottom block can receive without the top block moving? The surface between the bottom block and the ground is frictionless. I...

You have to use kinematics to determine what the velocity is at half the height, THEN you can use the momentum formula. HINT: the system has constant acceleration!

So center of mass isn't needed at all? I just assumed it would be because the question came out of the center of mass chapter in my textbook.

Yeah, I caught that error. How to get the average force still boggles me though

It is possible to solve it with the information given :wink: just think about it logically and take a look at that Vavg formula.

Just plug in the values you know to the average velocity formula and set vf to x :smile:

Yep, that's one way to do it. You could also use the cosine law. x = [26^2 + 62^2 - 2(26)(62)(cos 120)] ^ .5 x = 78.3