Recent content by twenty5

ah kay, thank youuuu ^^ is there like a thank button somewhere?

Homework Statement Determine the radius of a highway curve which has a banking angle of 6% over which vehicles will travel at 120km/h Homework Equations I've started with: Fx = -Fcentripetal = (mv2)/r = -Fnsin6 (mv2)/2 = mgsin6 converted my km/h => m/s ... 33.3m/s The...

sorry d = distance, I should have put s instead xD I also put C = 2(pi)r ... = d ... therefore d = C and naww, I don't think any of my profs care haha.. it's a habit of mine :)

they both seem to be okay... but the masses are different! I don't want to get this wrong on the test :S we're solving for the mass. Everything on the diagram is what was given and calculated

Homework Statement I have a pendulum sitting at 15 degrees from the vertical, it does 1 revolution every 2 seconds. the chain is 1.0m long. The tension is 2.0N My question is which Method would be correct? My professor said, that Method I is the same a Method II (the ones I wrote on the...

I'm starting to come in from the right end, and it's starting to match up.. I think I'm doing it correctly ^^. I like to talk to myself thanks guys.

Homework Statement Calculate the truss' member forces using method of sections. Homework Equations Fx=0 Fy=0 M (any point) = 0 [PLAIN]http://img97.imageshack.us/img97/4482/haalp.png The Attempt at a Solution I have half of it done, but the numbers are beginning to get...

OOOH NVM NVM NVM NVM.; I GOT IT. thanks for the consideration of this thread though. ^^ For those who may also encounter this ^^ you have to use the moment equations to get the reactions at the supports. From this, you can calculate the rest of the values ^^ very happy. thanks ( thanking...

Homework Statement hi all, I've got a simple truss question. Which asks to solve for the member forces. I've learned the stuff in class, but from what I see here, I don't know which joint to start with. With the provided image below, can someone please direct me to which joint I should start...

ah. okay thank you very much sir.

mmk. Because I was taught that the gravitational acceleration (g) is always doing straight down :) but I'll give it a go with it being perpendictular to the 15°. thank you very much my friend ^^

the only other way I would get a component for the gravitational acceleration would be if I had made it perpendicular to the 15° incline :(

I made a drawing but it's point straight down :/

would that be A = (Vf - Vi) / t AT + Vi = Vf how would one use the incline part? since gravity is going straight down vertically, there wouldn't really be any components other than 9.81 :S

well I diid all of that and I 2.83 seconds. I used that and stuck it into v = d/t and I got d = 78.59m. Can you please check to see if this is the correct answer? please and thank you ^^