URGENT PLEASE HELP! Chemistry Related Math/Hydraulic Problems I Can't Get
Got a test tomorrow on this stuff. If I know how to attack these problems, I will be ok.
1. A water plant treats a flow of 9.0 ML/d. the Mix chamber is 0.75m x 0.75m and the depth of water is 1.0m. Flocculation basin...
I don't know how to get the vertical.. There is no example.
Would I use trig to find the vertical? hypotaneuse being 25, inside angle being 25, and figure out the opposite side(vertical)?
Question 2
W=Fs(costheda)
W=(200N)(25.0m)(cos25.0degrees)
W=4531 N
This is incorrect though.. I don't know.. This is just frustrating me now. They don't give examples for this in the book.
Ok I am getting two different answers and it is just confusing me. This is what I did for 1 a)
W=Fs
W=(215N)(4.20m)
W=903Nm or J
1 b)
W=Fs
W=(-215N)(4.20m)
W=-903Nm or J
These are both the final answers in the book, however I am still confused about what we do with the horizontal 6.80m.
I wouldn't agree with you. If the displacement is 0 than the work would be 0, however there is a displacement of 4.20m, plus the final answer is also 903 Joules or Newton Metres in the back of the text. So the answer cannot be 0.
Two Work problems I can't figure out. I don't really know where to start?
Question1) A delivery person carries a 215N box up stairs 4.20m vertically and 6.80m horizontally.
a)How much work does the delivery person do?(Answer: 903 J)
b)How much work does the delivery person do in carrying the box...
1. A ball weighing 520g is thrown straight up at 6.0m/s
a) What is the initial momentum of the ball in N.s
2. p=mv
=520g(1kg/1000g)(6.0m/s)
=3.12
=3.1 N.s
I don't see how this is correct because it takes kg.m.s^2 to create a Newton. There is none here.
Then we go on to...
Q1: Assuming friction force to be negligibly small, what will be the acceleration in m/s^2 of a 45kg skater when propelled by a force of 250N?
My attempt
Data:
F-250N
m-45kg
a-m/s^2
Formula:
F=ma
a=F/m
a=250N/45kg
a=5.555
a=5.6m/s^2
Q2: a 0.5kg mass on a horizontal frictional free...