Recent content by utnip123
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Engineering Node Voltage Circuit Analysis: Solving for V1, V2, and V3
Hi, I am given a node voltage problem to find V1, V2, and V3 from this image below. http://puu.sh/77Sg3.png (v1+15)/20 + (v1-v2)/25 + (v3-v2)/50 + (v3 - 10)/10 = 0 18V1 - 12V2 + 24V3 = 50 V2: (v2-v1)/25 + v2/40 + (v2-v3)/50 = 0 17V2 - 8V1 - 4V3 = 0 15 = V3 - V1 Am I in...- utnip123
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- Analysis Circuit Circuit analysis Node voltage Voltage
- Replies: 1
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
(Vb - Va)/40 + (Va - Vb)/20 + (Vb - Va)/40 = 0 Va = (.003)(40) = .12 V Did i set this up right?- utnip123
- Post #13
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
I think i see where this is going. They are all connected in the same way. Aren't they all short circuited?- utnip123
- Post #9
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
Oh starting from the Current source, I see 2 different paths.- utnip123
- Post #7
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
I believe I'm seeing 4 nodes, 1 at the left and right, and 2 in the middle.- utnip123
- Post #5
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
Well in the other two loops there are no circuit elements, and there is only one current source. Should i instead go through this with nodal analysis?- utnip123
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Engineering Series Resistive Circuit Problem Solution
Homework Statement http://puu.sh/6PZNJ.png Homework Equations This is supposed to be a pretty easy problem, but can i assume the resistors are in series? The other loops are throwing me off. The Attempt at a Solution- utnip123
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- Circuit Resistive circuit Series
- Replies: 13
- Forum: Engineering and Comp Sci Homework Help
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Graduate Did I solve this diff eq substition problem properly?
xy'=yln(xy) xdy=yln(xy)dx \frac{dy}{y}=\frac{ln(xy)dx}{x} Substitution: v=ln(xy) dv = \frac{dy}{y}-\frac{dx}{x} dv-\frac{dx}{x}=\frac{vdx}{x} ∫\frac{dv}{v+1}=∫\frac{dx}{x} ln(v+1)=ln x + C v+1 = Cx ln(xy) +1 = Cx Would that basically be the complete answer?- utnip123
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- Diff eq
- Replies: 1
- Forum: Differential Equations
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Torque- rigid objects in equalibrium/ center of gravity.
Homework Statement A uniform door(.81m wide and 2.1m high) weighs 140N and is hung on two hinges that fasten the long left side of the door to a vertical wall. The hinges are 2.1m apart. Assume that the lower hinge bears all the weight of the door. Find the magnitude and direction of the...- utnip123
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- Center Center of gravity Gravity Torque
- Replies: 3
- Forum: Introductory Physics Homework Help