Recent content by vanceEE

Just posted it, must be a misprint because three components of the vector would need to be included whether zero or not, so according to the solution, I believe that the author meant that the velocity vector was <2*10^7, 1*10^7, -3*10^7>m/s

How was the magnitude of the velocity vector found in the example provided? This is a particle in space so I has 3 coordinates but I am told that the velocity vector is m/s, so wouldn't the magnitude just be 2*10^7 m/s?

Homework Statement Drawing surface ##f(x,y) = ...## or ##r(t) = <f(t),g(t)>## etc. The Attempt at a Solution I've been working on drawing space curves lately, by breaking into separate planes and by level curves. I'm struggling w/ this topic. (1) If I'm not mistaken, this is fundamental in...

Hi, these we're very helpful, but I'm looking for instructions on plotting and conceptualizing space and vector curves rather than single points e.g. ##r(t) = <f(t),g(t),h(t)>## Thanks.

What are some helpful strategies for drawing and conceptualizing space curves? I'm having trouble drawing them and I'm not very artistic! Also, please provide helpful videos on this topic if you can. Thanks.

Ok, thanks for the help!

Are the bright fringe to bright fringe considered to be 1st order? For example, would the middle-fringe (green) be zero and the first two greens on the top and bottom of the middle fringe be considered first order? http://h2physics.org/wp-content/uploads/2009/08/young2a.jpg If so, then the...

$$ θ = tan^{-1}(\frac{|CB|}{1.8}) = tan^{-1}(\frac{4.6*10^{-3}}{1.8}) = 0.1464° $$ B is 2nd order, hence n = 2. $$(0.25*10^{-3})sin(0.1464°) = 2λ$$ $$λ = \frac{(0.25*10^{-3})sin(0.1464°)}{2} = 319.4 nm$$ Please explain; I am still getting the same wavelength.

Here are the basic rules for uncertainty: Addition/Subtraction $$(A ± ΔA) + (B ± ΔB) = (A+B) ± (ΔA+ΔB)$$ $$(A ± ΔA) - (B ± ΔB) = (A-B) ± (ΔA+ΔB)$$ When dividing and multiplying, changing to relative uncertainty, then converting back simplifies things. where: $$ε = \frac{ΔA}{A}*100$$ 'relative...

Homework Statement In Fig. 6.1 the distance from the two slits to the screen is 1.8 m. The distance CP is 2.3 mm and the distance between the slits is 0.25 mm. Calculate the wavelength of the light provided by the laser. Homework Equations $$asinθ = nλ$$ $$w = \frac{λD}{a}$$ The Attempt at a...

Please disregard, I came up with a solution! $$P(445-c≤x≤445+c) = 0.94$$ $$P(\frac{-c}{3.6}≤z≤\frac{c}{3.6}) = 0.94$$ $$\phi(\frac{c}{3.6})-\phi(\frac{-c}{3.6}) = 0.94$$ $$\phi(\frac{c}{3.6})-[1-\phi(\frac{c}{3.6})] = 0.94$$ $$2\phi(\frac{c}{3.6}) = 1.94$$ $$\phi(\frac{c}{3.6}) = 0.97$$...

Homework Statement "Cans of lemon juice are supposed to contain 440 ml of juice. It is found that the actual volume of juice in a can is normally distributed with mean 445 ml and standard deviation 3.6 ml." It is found that 94% of the cans contain between 445−c ml and 445+c ml of juice. (ii)...

"Radium-226 has a half-life of 1,620 years, which means that half of a given sample of radium-226 will decay into lead by the end of 1,620 years. In the next 1,620 years, half of the remaining sample will decay into lead, leaving one-fourth of the original amount of radium-226."(1) Wouldn't...

I've never heard of a "minimum" coefficient when dealing with friction. The coefficient is constant unless conditions change e.g. rough to smooth surface. We must assume that the car is on point of moving (limiting equillibrium), therefore letting a = 0. Letting a equal zero does not imply that...