Recent content by veloix

thanks man that was right. i got same thing :). I appreicate the help.

hmm some calculations i did from this were w^2=k/m (2*pi*1.6)^2=k/1464.4= 147992.264 K= 101.06*1464.4= 147992.264 n/m ok now i tired your equation delta_F=k*delta_x=> Mg-weight of men= delta_x so (1464.4)(9.80)-(71.1*4)= delta x= 14066.72 this was wrong. I also notice what happen to k?

[SOLVED] Simple Harmonic Motion Homework Statement Four people, each with mass of 71.1 kg, are in a car with a mass of 1180 kg. An earthquake strikes. The vertical oscillations of the ground surface make the car bounce up and down on its suspension springs, but the driver manages to pull of...

fy=mv^2/r+mg Fy=(9.108*10^-31)(2*10^6)^2/(5.5*10^-11)+(9.108*10^-31)(9.80) = 6.6*10^-8 still off by magnitudes i don't what to do

but i still get the wrong answer.

ah the mass of the electron

atomic mass ?

Homework Statement In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.00 x 10^6 m/s. (a) Find the force acting on the electron as it revolves in a circular orbit of radius 5.50x 10^-11 m Homework Equations ∑fy=ma=mv^2/r ac=v^2/r The Attempt...

i know the it shuold look like this xf=xi+vit 1900m= 0+(cos(theta)(992m/s)t

Homework Statement A cannon with a muzzle speed of 992 m/s is used to start an avalanche on a mountain slope. The target is 1900 m from the cannon horizontally and 793 m above the cannon. At what angle, above the horizontal, should the cannon be fired? (Ignore air resistance.) Homework...

oh yea that makes sense ty.

i can't draw this plot right I am haveing difficluty.

great that work out perfectly thank you part c asking for distance this time, the ∫d(t)?

oh that's why i got it wrong i had 2 written on my y-axis instead of 4, ugg. so to get the speed at 12s i would get area of each rectangle and add them up.

the area of the rectanlge would 6X2=12